The class can break or if you put it in cold water it can cool down down fast.
Answer:
The table tennis balls represent neutrons that are released when the nucleus splits and cause other nuclei to split
Explanation:
Nuclear fission is defined as the separation of a nucleus into two smaller nuclei.
It takes a neutron to set off a nuclear fission reaction. When that occurs, neutrons are released and those neutrons in turn are what set off other nuclear fissions. This is defined as a Nuclear Fission Chain Reaction. In the model, the one tennis ball that will be thrown will be modeled as the starting neutron that sets of the initial (first) fission. The mouse traps with tennis balls represent the other nucleuses waiting to be struck by the one tennis ball. Once the initial tennis ball strikes the first mouse trap, that mouse trap will release its tennis ball hitting others and continuing the cycle.
It can also be modeled as such:
The flow/transfer of energy
<u>Answer:</u> 1.461 g of NaCl is dissolved in the solution.
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.
The formula used to calculate molarity:
.....(1)
Given values:
Molarity of solution = 0.050 M
Molar mass of NaCl = 58.44 g/mol
Volume of solution = 500.0 mL
Putting values in equation 1, we get:
![0.050=\frac{\text{Given mass of NaCl}\times 1000}{58.44\times 500}\\\\\text{Given mass of NaCl}=\frac{0.050\times 58.44\times 500}{1000}\\\\\text{Given mass of NaCl}=1.461g](https://tex.z-dn.net/?f=0.050%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20NaCl%7D%5Ctimes%201000%7D%7B58.44%5Ctimes%20500%7D%5C%5C%5C%5C%5Ctext%7BGiven%20mass%20of%20NaCl%7D%3D%5Cfrac%7B0.050%5Ctimes%2058.44%5Ctimes%20500%7D%7B1000%7D%5C%5C%5C%5C%5Ctext%7BGiven%20mass%20of%20NaCl%7D%3D1.461g)
Hence, 1.461 g of NaCl is dissolved in the solution.
Answer: The empirical formula is C₃H₃O.
Explanation: Assume we have 100 g of the compound. Then we have 65.65.5 g of C, 5.5 g of H, and 29.0 g of O.