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zzz [600]
3 years ago
12

What is symbol, molecule, electrovalent compound?​

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

the abbreviation form of full name is called symbol.

the smallest unit of cimpound is called molecule.

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What is the density of a object whose dimensions are 5.54
Tcecarenko [31]

The object with dimensions 5.54\ cm \times 10.6\ cm \times 199\ cm and with mass 250.6 g will have a density equal to 0.02144\ g/cm^3.

<h3><u>Explanation:</u></h3>

<u>Given:</u>

Dimensions of the object = 5.54\ cm \times 10.6\ cm \times 199\ cm

length = l = 5.54 cm

width = w = 10.6 cm

height = h = 199 cm

Mass of the object = m = 250.6 g

<u>Formula:</u>

The relation between density, mass and volume of any object is given by:

Density = \frac{ Mass }{Volume}

Since volume of an object with length (l), width (w) and height (h) [assuming a rectangular object] can be defined as,

V = l \times w \times h =5.54 \times 10.6 \times 199

Volume = V = 11686.076\ cm^3

Density = Mass / Volume = \frac{250}{11686.076}

Density = 0.02144 g/cm^3

Density of the object is 0.02144 g/cm^3

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3 years ago
The three states of matter are solid, liquid, and gas. true or false
maria [59]
That is True XD
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3 years ago
g The following reaction is the first step in the production of nitric acid from ammonia. 4NH3(g) 5O2(g) → 4NO(g) 6H2O(g) Calcul
STatiana [176]

<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]

We are given:

\Delta H_f_{(NO(g))}=91.3kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-45.9kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ

Hence, the enthalpy of the reaction is coming out to be -902 kJ.

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Which do all groups of plants have these are the choices A.chloroplasts B.roots C.spores D.tubes
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What's the atomic mass unit of helium?
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4.002602 u ± 0.000002 u
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