Answer:
Water plays a very important role in chemical weathering in three different ways. First, it combines with carbon dioxide in the soil to form a weak acid called carbonic acid. ... Finally, the water can break up minerals through hydrolysis. The most common group of minerals, the silicates, is decomposed by this process.
Answer:
459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution
Explanation:
Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.
The Molarity of a solution is determined by the following expression:

Molarity is expressed in units 
In this case:
- Molarity: 1.56 M= 1.56

- Number of moles of calcium chlorine= ?
- Volume= 2.657 liters
Replacing:

Solving:
Number of moles of calcium chlorine= 1.56 M* 2.657 liters
Number of moles of calcium chlorine= 4.14 moles
In other side, you know:
- Ca: 40 g/mole
- Cl: 35.45 g/mole
Then the molar mass of the calcium chloride CaCl₂ is:
CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole
Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass= 459.126 g
<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>
Answer:
b consumers eat producers
Explanation:
In a food chain, the consumers are living organisms that eat organisms from a different population. Examples are herbivores like goats.
Producers make their own food in the food chain. Examples are plants.
The relationship between consumer and producers is hence that consumers consume / eat producers. Goats eat grass.
The correct option is;
b consumers eat producers
50ml = 50cm³ = 0,05dm³
C = n/V
n = 0,15 mol/dm³ × 0,05dm³
n = 0,0075 mol CH₃COOH
..............................
CH₃COOH + NaOH ----> CH₃COONa + H₂O
1 mol...............1 mol
1 mol CH₃COOH ------------1 mol NaOH
0,0075 mol CH₃COOH --- X
X = 0,0075 mol NaOH
V = n/C
V = 0,0075/0,1
V = 0,075 dm³ = 75cm³ = 75 mL