NaHCO3
That is the formula for baking soda
By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.
<h3>What are the limits?</h3>
First, we need to find the limits.
We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.
So if 58 in is the 100%, the 26% and 43% of that are:
- 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
- 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.
But we know that the CG is found to be 45.5% MAC, then it measures:
(45.5%/100%)*58in = 0.455*58in = 26.39 in
We need to compare it with the largest limit, so we get:
26.39 in - 24.94 in = 1.45 in
This means that the CG is 1.45 inches out of limits.
If you want to learn more about percentages, you can read:
brainly.com/question/14345924
Answer:
the assessment is due at 11 you only have 1 hour do it fasst
Explanation:
the assessment is due at 11 you only have 1 hour do it fasst
Answer:
180 m
Explanation:
The rock follows a free-fall motion - so the vertical distance covered can be found by using the equation

where
g = 10 m/s^2 is the acceleration due to gravity
t = 6.00 s is the time of the fall
Substituting these data, we find the height of the cliff:

Their are two coefficients of friction, static and kinetic, regardless, they have basically the same formula:
u*N = F... aka
coefficient of friction*normal force = force of friction
Hope that helps!