Answer:
The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Explanation:
Given;
velocity of wave on the string with lower tension, v₁ = 35.2 m/s
the fundamental frequency of the string, F₁ = 258 Hz
<u>velocity of wave on the string with greater tension;</u>

where;
v₁ is the velocity of wave on the string with lower tension
T₁ is tension on the string
μ is mass per unit length

Where;
T₁ lower tension
T₂ greater tension
v₁ velocity of wave in string with lower tension
v₂ velocity of wave in string with greater tension
From the given question;
T₂ = 1.1 T₁

<u>Fundamental frequency of wave on the string with greater tension;</u>
<u />
<u />
Beat frequency = F₂ - F₁
= 270.6 - 258
= 12.6 Hz
Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
A similar but separate notion is that of velocity, which the rate of change<span> of </span>position<span>. Example . If p(t) is the </span>position<span> of an </span>object<span> moving on a number line at time t (measured in minutes, say), then the average </span>rate of change<span> of p(t) is the average velocity of the </span>object<span>, measured in units per minute.</span>
Answer:
Amount of work done by Joanne = 80 joule
Explanation:
Given:
Displacement of ball = 2 meters
Force applied = 40 newtons
Find:
Amount of work done by Joanne
Computation;
Work done = Force applied x Displacement
Amount of work done by Joanne = Force applied x Displacement of ball
Amount of work done by Joanne = 40 x 2
Amount of work done by Joanne = 80 joule
Since you didn't tell us the choices, I can pick anything I like.
The one that always does it for me is " foaming brine " .