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Aleonysh [2.5K]
3 years ago
10

Which equation represents a combustion reaction? Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3 2SO2 + O2 → 2SO3 2C2H6 + 7O2 → 4CO2 + 6H2O Ca +

2HCl → CaCl2 + H2
Physics
2 answers:
Arturiano [62]3 years ago
5 0

Answer:

2C_2H_6+7O_2\rightarrow4CO_2+6H_2O it is a combustion reaction.

Explanation:

Combustion reaction is the type of reaction in which a hydrocarbon heated up in the presence of oxygen to form water and carbon dioxide.

C_2H_6 is ethane and it is a hydrocarbon. The combustion reaction of ethane is as follows :

2C_2H_6+7O_2\rightarrow4CO_2+6H_2O

So, the correct option is (c).

Naddik [55]3 years ago
3 0

Answer:

2C2H6 + 7O2 → 4CO2 + 6H2O

Explanation:

Combustion is when a hydrocarbon (a compound made of only hydrogen and carbon) reacts with oxygen at high temperature to produce CO2 and H2O gases.

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A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

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K=\frac{1}{10}E

Since we have

K=E-U

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E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

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