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Aleonysh [2.5K]
2 years ago
10

Which equation represents a combustion reaction? Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3 2SO2 + O2 → 2SO3 2C2H6 + 7O2 → 4CO2 + 6H2O Ca +

2HCl → CaCl2 + H2
Physics
2 answers:
Arturiano [62]2 years ago
5 0

Answer:

2C_2H_6+7O_2\rightarrow4CO_2+6H_2O it is a combustion reaction.

Explanation:

Combustion reaction is the type of reaction in which a hydrocarbon heated up in the presence of oxygen to form water and carbon dioxide.

C_2H_6 is ethane and it is a hydrocarbon. The combustion reaction of ethane is as follows :

2C_2H_6+7O_2\rightarrow4CO_2+6H_2O

So, the correct option is (c).

Naddik [55]2 years ago
3 0

Answer:

2C2H6 + 7O2 → 4CO2 + 6H2O

Explanation:

Combustion is when a hydrocarbon (a compound made of only hydrogen and carbon) reacts with oxygen at high temperature to produce CO2 and H2O gases.

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3 years ago
A 5kg rock and a 10kg rock are dropped from a height of 10m?
fredd [130]
Look out below ! You should step nimbly to one side, to avoid being hit by one or the other of those hazardous weight objects when they arrive (at the same time).
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2 years ago
The speed at which a light aircraft can take off is 120 km/h. (A) What is the minimum constant acceleration required for the pla
kondor19780726 [428]

Answer:

A) a = 2.31[m/s^2]; B) t = 14.4 [s]

Explanation:

We can solve this problem using the kinematic equations, but firts we must identify the data:

Vf= final velocity = take off velocity = 120[km/h]

Vi= initial velocity = 0, because the plane starts to move from the rest.

dx= distance to run = 240 [m]

v_{f} ^{2} =v_{i} ^{2}+2*g*dx\\where:\\v_{f}=120[\frac{km}{h} ]*\frac{1hr}{3600sg} * \frac{1000m}{1km} =33.33[m/s]\\\\Replacing\\33.33^{2}=0+2*a*(240)\\ a=\frac{11108.88}{2*240}\\  a=2.31[m/s^2]\\

To find the time we must use another kinematic equation.

v_{f} =v_{i} +a*t\\replacing:\\33.33=0+(2.31*t)\\t=\frac{33.33}{2.31}\\ t=14.4[s]

7 0
3 years ago
If an object is moving eastward and slowing down, then the direction of its acceleration vector is
iragen [17]
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8 0
3 years ago
If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.

5 0
2 years ago
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