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kenny6666 [7]
3 years ago
13

Find the same of 136+ 212 explain why you did not regroup

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
136+212=348 this is just adding, no regrouping required
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Your looking at a map with a scale of inch
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Dana has 800 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed are
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As per the given statement, Dana has 800 yards of fencing to enclose a rectangular area.

Therefore, perimeter of rectangle = 800 yards.

Perimeter(P) of rectangle is given by :

P = 2(x+y) where x is the length and y is the width of the rectangles respectively.

Then,

2(x+y) = 800

Divide both sides by 2 we get;

x+y =400

or

y = 400 -x            .....[1]

We know, the area(A) of rectangle is given by

A = xy                   .....[2]

Substitute equation [1] into [2] we get;l

A = x(400-x)

using distributive property a\cdot (b+c) = a\cdot b+ a\cdot c

A = 400x -x^2            

or

A =-x^2+400x    ......[3]

To maximize the enclosed area.

For a quadratic function in standard form y =ax^2+bx+c , the axis of symmetry is a vertical line given by;  

x = -\frac{b}{2a}

Then; we have from equation [3]

a = -1 and b = 400

By axis of symmetry;

x = -\frac{b}{2a} = -\frac{400}{2 \cdot -1} =\frac{400}{2} = 200

Substitute in equation [1] to solve for y:

y = 400 - 200 = 200

The dimensions of the rectangle that maximize enclosed area are:

x = 200 units and y = 200 units.

Maximum area = 200 \times 200 = 40,000 square units.

We can say that maximum area of rectangle will always be a square



4 0
3 years ago
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