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kenny6666 [7]
3 years ago
13

Find the same of 136+ 212 explain why you did not regroup

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
136+212=348 this is just adding, no regrouping required
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vladimir1956 [14]

Answer:

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These are the nonvascular plants or bryophytes (mosses, liverworts, and hornworts), the seedless vascular plants (clubmosses and ferns including, horsetails, club mosses, and whisk ferns), gymnosperms (conifers, cycads, Ginkgo, and gnetophytes), and angiosperms, or flowering plants.

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2 years ago
Thirteen is seven more than one fifth of a number //how do you right that as an equation?
Bumek [7]
The answer is 13= 7+1/5n
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3 0
3 years ago
If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1​
Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0
2 years ago
I need help!!! I just need the answer for p and i also need the answer step by step!!
klasskru [66]

Answer:

  x = 18

  m = 21.2

  p = 31.8

Step-by-step explanation:

The ratio of the left-side length to the bottom-side length is the same for both triangles:

  x/11.2 = (x +27)/28

  28x = 11.2(x +27) = 11.2x +302.4 . . . . . multiply by 11.2·28

  16.8x = 302.4 . . . . . . . subtract 11.2x

  x = 18 . . . . . . . . . . . . divide by 16.8

__

The length of m can be found using the Pythagorean theorem. The sum of the squares of the legs is the square of the hypotenuse.

  x^2 +11.2^2 = m^2

  m = √(324 +125.44) = √449.44 = 21.2

__

The length of p can also be found using the Pythagorean theorem. We prefer the proportion ...

  p/27 = m/x

  p = 27(21.2/18) = 31.8

The lengths of the unknown sides in the figure are ...

  x = 18

  m = 21.2

  p = 31.8

8 0
2 years ago
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