Answer:
60 Ω
Explanation:
R(com) = 15 Ω
1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn
1/15 = 1/20 + 1/R2
1/R2 = 1/15 - 1/20
1/R2 = (4 - 3) / 60
1/R2 = 1/60
R2 = 60 Ω
así, la combinada de resistencia necesaria es 60 Ω
Answer:
length of one side of the coil is 0.1083 m
Explanation:
given data
no of turn = 269
coil rotates = 113 rad/s
magnetic field = 0.222-T
peak output = 79.2 V
solution
we will apply here formula for maximum emf induced in a coil that is
εo = N × A × B × ω ........................1
and here Area A = l²
so
l =
put here value of A from equation 1
I =
put here value and we will get
l = 
l = 0.1083 m
Answer:
F = 32 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = forces applied [N] (units of Newtons)
m = mass = 40 [kg]
a = acceleration = 0.8 [m/s²]
Now replacing:
![F=m*a\\F = 40*0.8\\F = 32 [N]](https://tex.z-dn.net/?f=F%3Dm%2Aa%5C%5CF%20%3D%2040%2A0.8%5C%5CF%20%3D%2032%20%5BN%5D)
When a net torque is applied to a rigid object, it always produces a <em>change in angular velocity</em>. <em>(e.)</em>