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Georgia [21]
4 years ago
7

How can I find the center of gravity of a human being?

Physics
1 answer:
Masteriza [31]4 years ago
5 0
BY THINKING AND USING PHISYCS
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¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
What is a mixture of rock and mineral fragments, organic matter, air, and water called?
Gekata [30.6K]
The answer should be soil
7 0
4 years ago
A generator has a square coil consisting of 269 turns. The coil rotates at 113 rad/s in a 0.222-T magnetic field. The peak outpu
Natalka [10]

Answer:

length of one side of the coil is 0.1083 m

Explanation:

given data

no of turn = 269

coil rotates = 113 rad/s

magnetic field = 0.222-T

peak output = 79.2 V

solution

we will apply here formula for maximum emf induced in a coil that is

εo = N × A × B × ω    ........................1

and here Area A = l²

so

l = \sqrt{A}

put here value of A from equation 1

I = \sqrt{\frac{\epsilon _o}{N\times B\times \omega} }  

put here value and we will get

l =  \sqrt{\frac{79.2}{269\times 0.222\times 113}}

l = 0.1083 m

5 0
4 years ago
Read 2 more answers
If the boy and his bike actually had a mass of 40 kg instead of 50 kg how much force would it take for him to accelerate at 0.8
klio [65]

Answer:

F = 32 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N] (units of Newtons)

m = mass = 40 [kg]

a = acceleration = 0.8 [m/s²]

Now replacing:

F=m*a\\F = 40*0.8\\F = 32 [N]

8 0
3 years ago
Complete the following statement: When a net torque is applied to a rigid object, it always produces a:______.
Tatiana [17]

When a net torque is applied to a rigid object, it always produces a <em>change in angular velocity</em>. <em>(e.)</em>

7 0
3 years ago
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