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hichkok12 [17]
3 years ago
14

The tension in the horizontal cord is 30N. Find the weight of the object.

Physics
1 answer:
vazorg [7]3 years ago
7 0
Making a drawing of the system, we will have two forces which are tension and the weight of the object. Balancing the forces present, we do as follows:

T = W
W = 30 N

Therefore, weight is equal to 30 N. Hope this answers the question. Have a nice day. Feel free to ask more questions.
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9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.
Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength \lambda is the distance between to crests; this means we have 4\lambda in 40 m:

40 m=4\lambda

Clearing \lambda:

\lambda=\frac{40 m}{4}

\lambda=10 m

b) This part can be solved by a Rule of Three:

If 10 waves ---- 16 s

1 wave ----- T

Then:

T=\frac{(1 wave)(16 s)}{10 waves}

T=1.6 s This is the period of the wave

On the other hand, the frequency f of the wave has an inverse relation with its period T:

f=\frac{1}{T}

f=\frac{1}{1.6 s}

f=0.625 Hz This is the frequency of the wave

c) The speed v of a wave is given by the following equation:

v=\frac{\lambda}{T}

v=\frac{10 m}{1.6 s}

Finally:

v=6.25 m/s

4 0
3 years ago
A baseball is thrown vertically into the air with a speed of 24.7 m/s.
zmey [24]

Answer:

57.7

Explanation:

3.14 × 23 + - 78 = 57.7

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2 years ago
Regions in the milky way where density waves have caused gas clouds to crash into each other are called
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Regions in the milky way where density waves have caused gas clouds to crash into each other are called clumps.Clumps are molecular clouds (interstellar clouds) with higher density,where lots of dust and gs cores resides. These clouds are the beginning of stars.
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The general formula for an acid is
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Answer:

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Explanation:

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3 years ago
An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
shepuryov [24]

Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

m is the mass of the electron

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Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

And solving for v, we find an expression for the speed of the electron:

v=\sqrt{\frac{kZe^2}{mr}}

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