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hichkok12 [17]
3 years ago
14

The tension in the horizontal cord is 30N. Find the weight of the object.

Physics
1 answer:
vazorg [7]3 years ago
7 0
Making a drawing of the system, we will have two forces which are tension and the weight of the object. Balancing the forces present, we do as follows:

T = W
W = 30 N

Therefore, weight is equal to 30 N. Hope this answers the question. Have a nice day. Feel free to ask more questions.
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2 years ago
A transverse, travelling wave on a chord is represented by = 0.22sin (5.6 + 34) where and are in meters and is in seconds. For t
Neko [114]

Answer:

A)  1.122 m

B)  5.4 hertz

C)  6.06 m/s ( towards negative  x axis )

D)  0.22

E)  max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

  minimum speed ( speed at rest ) = 0

Explanation:

The travelling wave = D = 0.22sin ( 5.6x + 34t)

this wave is represented in the form : D = Asin ( kx + wt)

A) wavelength

k = 2\pi / v

v = wavelength

k = 5.6

therefore wavelength ( v ) from the equation = 2\pi / 5.6 = 1.122 m

B ) frequency

w = 2\pif

w = 34

f = frequency

therefore f = w / 2\pi  = 34 / 2\pi = 5.4 hertz

C ) velocity

speed = f v

v = 5.4 * 1.122 = 6.06 m/s ( towards negative  x axis )

D) amplitude

A = 0.22

E ) maximum and minimum speeds of particles on the chord

max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

minimum speed ( speed at rest ) = 0

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