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igor_vitrenko [27]
3 years ago
8

Critical mass depends on ___. Check all that apply.

Physics
1 answer:
mario62 [17]3 years ago
3 0
The critical mass of a fissionable material depends upon its nuclear properties (specifically, the nuclear fission cross-section), its density, its shape, its enrichment, its purity, its temperature and its surroundings.
i hope this helps. if it does please mark brainliest.
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While buying a hot plate you notice the resistance of the hot
marissa [1.9K]

Answer:

Current = 5.45amps

Power = 654 watts

Explanation:

E =120V

I =?

R = 22.02 Ohms

I= E/R

I= 120/22.02

I = 5.45AmPs

P = ?                    P= E x R

E = 120V              P= 120x5.45

I = 5.45 AmPs      P=  654W

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1 year ago
What would be the distance moved if we had a 70 n force and work done is 8j
Lostsunrise [7]

Answer:

0.1143m

Explanation:

W=f×s

8=70s

make s the subject of the formula

s=8/70

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2 years ago
The ph of an acidic substance ia between what values on the ph scale
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0 - 6 is acidic

7 is neutral

8 - 14 is basic

7 0
3 years ago
Two small insulating spheres with radius 9.00*10^-2m are separated by a large center-to-center distance of 0.520m . One sphere i
Ganezh [65]

British realized their northern strategy had failed

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3 years ago
A solid circular plate has a mass of 0.25 kg and a radius of 0.30 m. It starts rolling from rest at the top of a hill 10 m long
KATRIN_1 [288]

To solve the problem it is necessary to apply the equations related to the conservation of both <em>kinetic of rolling objects</em> and potential energy and the moment of inertia.

The net height from the point where it begins to roll with an inclination of 30 degrees would be

h=Lsin30

h=10sin30

h=5m

In the case of Inertia would be given by

I = \frac{mR^2}{2}

In general, given an object of mass m, an effective radius k can be defined for an axis through its center of mass, with such a value that its moment of inertia is

I = mk^2

\frac{mR^2}{2}= mk^2

\frac{k^2}{R^2}=\frac{1}{2}

Replacing in Energy conservation Equation we have that

Potential Energy = Kinetic Energy of Rolling Object

mgh = \frac{1}{2}mv^2(1+\frac{k^2}{r^2})

9.8*5=\frac{1}{2}v^2(1+\frac{1}{2})

v^2 (1.5) = 98

v=8.0829m/s

Therefore the correct answer is C.

3 0
3 years ago
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