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never [62]
3 years ago
7

Diabatic processes occur when:

Physics
1 answer:
Svetach [21]3 years ago
4 0

Answer:

The correct answer is d. add or remove energy from a system.

Explanation:

A diabatic process can be defined as one where a system exchanges energy with the surroundings resulting in a thermodynamic change of the system's state.

Diabatic processes can be grouped into five categories viz

1. Terrestrial radiation.

2. Solar radiation

3. latent heat flux

4. sensible heat flux

5. friction process

In the same vein, an adiabatic process is one in which there is zero heat, mass or momentum transfer across the bounary of the thermodynamic  system

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Describe what happens to chromosomes before mitosis.
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Explanation:

Before mitosis, the chromosomes are copied. They then coil up, and each chromosome looks like a letter X in the nucleus of the cell. The chromosomes now consist of two sister chromatids. Mitosis separates these chromatids, so that each new cell has a copy of every chromosome

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3 years ago
Apply the concept of density to explain why oil floats on water.
Sauron [17]
Anything less dense than water will float, like oil. Anything more dense than water will sink, like rock.
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how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?
egoroff_w [7]
F = m*a, mass times acceleration.

F = 15*10 = 150 N
8 0
3 years ago
Read 2 more answers
I need help, please answer
Burka [1]

This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.

7 0
3 years ago
A 50.0 kg child stands at the rim of a merry-go-round of radius 1.50 m, rotating with an angular speed of 3.00 rad/s. (a) what i
White raven [17]
Weight of the child m = 50 kg 
Radius of the merry -go-around r = 1.50 m
 Angular speed w = 3.00 rad/s
 (a)Child's centripetal acceleration will be a = w^2 x r = 3^2 x 1.50 => a = 9 x
1.5
 Centripetal Acceleration a = 13.5m/sec^2
 (b)The minimum force between her feet and the floor in circular path
 Circular Path length C = 2 x 3.14 x 1.50 => c = 3 x 3.14 => C = 9.424
 Time taken t = 2 x 3.14 / w => t = 6.28 / 3 => t = 2.09
 Calculating velocity v = distance / time = 9.424 / 2.09 m/s => v = 4.5 m/s
 Calculating force, from equation F x r = mv^2 => F = mv^2 / r => 50 x (4.5)^2

/ 1.5
 F = 50 x 3 x 4.5 => F = 150 x 4.5 => F = 675 N
 (c)Minimum coefficient of static friction u
 F = u x m x g => u = F / m x g => u = 675/ 50 x 9.81 => 1.376 
 u = 1.376
 Hence with the force and the friction coefficient she is likely to stay on merry-go-around.
8 0
3 years ago
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