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Mariulka [41]
3 years ago
5

Need help asap; put you as brainliest​

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

unmmmmmmmm I think the answerA

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When is it easiest for a person to build up static electricity?
Elena-2011 [213]
Idkk look it up on quizlet, they flash cards to tell you lots of stuff
3 0
4 years ago
A toy car with an initial velocity of 5 m/s slows to a stop with an acceleration of -1.5 m/s^2.
enot [183]

Car's Initial velocity (u) = 5 m/s

Car's Final velocity (v) = 0 m/s (Stop)

Acceleration of the car (a) = -1.5 m/s²

Equation used to solve this problem:

\boxed{ \bf{ {v}^{2}  =  {u}^{2}  + 2as}}

By substituting values in the equation, we get:

\rm \longrightarrow  {0}^{2}  =  {5}^{2}  +2  \times ( - 1.5) \times s \\  \\   \rm \longrightarrow 0 = 25 - 3s \\  \\  \rm \longrightarrow 25 - 3s = 0 \\  \\  \rm \longrightarrow 25 - 25 - 3s =0  - 25 \\  \\  \rm \longrightarrow  - 3s =  - 25 \\  \\  \rm \longrightarrow 3s = 25 \\  \\  \rm \longrightarrow  \dfrac{3s}{3}  =  \dfrac{25}{3}  \\  \\  \rm \longrightarrow s = 8.3 \: m

\therefore Displacement of the toy car (s) = 8.3 m

4 0
3 years ago
A middle-age star that burns hydrogen is a A.neutron star B.white dwarf c.main sequence star D.pusar
Usimov [2.4K]
Hello!

The correct answer is C.

As we should know, a neutron star is a small cluster of neutrons. It is neither middle aged or able to burn hydrogen.
A white dwarf is a “mock planet” and has no impact on hydrogen.
A pulsar is a form of a neutron star, making C the only possible answer.
Main sequence stars are both middle aged and able to use hydrogen to form other substances.

I hope I helped!
4 0
3 years ago
WILL MARK BRAINLIST!!! only for correct answer<br> NEED CORRECT ANSWER ASAPPP
Nataly [62]

Answer:

number 4

Explanation:

The reflection of light happens when the light bounces off the reflecting surface. That is described by the last (bottom) schematics.

Therefore, select answer number 4.

5 0
3 years ago
The mass of the uniform cantilever is 1100 kg. Determine the force on the beam at A. Determine the force on the beam at B. Use C
Mashcka [7]

Answer:

Force A=-−2,697.75 N

Force B=13, 488.75 N

Explanation:

Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.

25 mg-20Fb=0

25*1100g=20Fb

Fb=25*1100g/20=1375g

Taking g as 9.81 then Fb=1375*9.81=13,488.75 N

The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g

-275*9.81=−2,697.75. Therefore, force A pulls downwards

Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle

8 0
3 years ago
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