****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)

In one area, the lowest angle of elevation of the sun in winter is 23° 18'. Find the minimum distance, x, that a plant needi

Softa [21]

Answer:

A plant needing full sun can be placed from a fence 4.63 ft high at a distance of 10.75 meter if the lowest angle of elevation of the sun in winter is 23° 18'.

Explanation:

The given figure shows the arrangement of sun, 4.63 ft high and plant needing full sun.

By using trigonometric result, tan θ = Opposite side/Adjacent side.

Substituting

tan(23° 18') = 4.63 ft/x

x = 4.63 ft/ tan(23° 18') = 10.75 m

So that a plant needing full sun can be placed from a fence 4.63 ft high at a distance of 10.75 meter.

4 0

3 years ago

Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr

slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

W = $F_{total} .d$

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} .d =\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}$

$F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}$

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

$F_{sprinter} = F_{total} + F_{wind} = 39.7 + 30 = 69.68 N$

7 0

3 years ago

Read 2 more answers

For each situation, identify when sound would travel faster and why?

Rudiy27

A. Outside on a summer day, there are less particles that the sound bounces off of (snow and wind absorb the sound)

B. Water, sound travels faster through denser objects. Water has a higher density than air.

C. High air pressure, sound moves faster through matter that is closer together. This can be said because sound can't travel through space. (There is no atmosphere and consistent particles in space for sound to go through)

D. A piece of steel, It's denser than wood and water.

E. 90% nitrogen and 10% helium, nitrogen is denser than helium so it will move faster

8 0

3 years ago

Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal forces, what is the wagon

s2008m [1.1K]

Answer:

The acceleration of the wagon is 3 m/s².

To calculate the acceleration of the wagon, we use the formula below.

Formula:

F = ma............. Equation 1

Where:

F = horizontal Force

m = mass of the wagon

a = acceleration of the wagon.

make a the subject of the equation

a = F/m.............. Equation 2

From the question,

Given:

F = 30 N

m = 10 kg

Substitute these values into equation 2

a = 30/10

a = 3 m/s²

Hence, the acceleration of the wagon is 3 m/s².

5 0

2 years ago

The pressure of a liquid is given by P = pgh. Calculate the pressure (in SI unit) if the

BlackZzzverrR [31]

Answer:

5000 Pa

Explanation:

First collect the data you've been given already and make sure to convert into the right units;

Density = 1 g/cm³ ...... 1000 Kg/ m³

acceleration due to gravity = 10 m/s²

Height = 50 cm......0.5 m

after collecting the data, use the formula to solve

pressure = pgh

 = 1000 × 10 × 0.5

 = 5000 Pa

hope this helps

6 0

3 years ago