Vo= 331+0.6T
360=331+0.6T
360-331=0.6T
29=0.6T
0.6T/29
T=6/290 so change it to simplest form and us formulas good luck
Answer:
499.73 m
Explanation:
We'll begin by calculating the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 25 °C
Final temperature (T₂) = –20° C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = –20 – 25
ΔT = –45 °C
Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:
Length at 25°C (L₁) = 500 m
Coefficient of linear expansion (α) = 12×10¯⁶ /°C
Change in temperature (ΔT) = –45 °C
Length at –20 °C (L₂) =?
α = L₂ – L₁ / L₁ΔT
12×10¯⁶ = L₂ – 500 / (500 × –45)
12×10¯⁶ = L₂ – 500 / –22500
Cross multiply
L₂ – 500 = 12×10¯⁶ × –22500
L₂ – 500 = –0.27
Collect like terms
L₂ = –0.27 + 500
L₂ = 499.73 m
Therefore, the length on a cold day at –20° C is 499.73 m.
Answer:
CH4
Explanation:
CH4 is joined together by a covalent bond, aka a bond between two non-metals. Non-metals are found on the right side of the periodic table and include Carbon (C) and Hydrogen. Although Hydrogen is technically on the left side of the table, it has the characteristics of a non-metal. Futhermore, Ionic bonds generally are between an element on the right joined with an element on the left. This is because ionic bonds want charges that will cancel out to create a neutral molecule.
example: LiF
Li→ Li+
F→F-
(Li+)+(F-)=charges cancel out.