Answer:
TIMED HELP ASAP
19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g･°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.
Answer:The molecular formula of the oxide of metal be 
. The balanced equation for the reaction is given by:
Explanation:
Let the molecular formula of the oxide of metal be 
Mass of metal product = 1.68 g
Moles of metal X =
1 mol of metal oxide produces 2 moles of metal X.
Then 0.03005 moles of metal X will be produced by:
of metal oxide
Mass of 0.01502 mol of metal oxide = 2.40 g (given)
y = 2.999 ≈ 3
The molecular formula of the oxide of metal be . The balanced equation for the reaction is given by:
<span>ΔE = -RH [(1/nf2) - (1/ni2)]ΔE = -2.18 x10-18 J [(1/32) - (1/52)]ΔE = -1.55 x10-19 JE = hc/λλ = hc/Eλ = [(6.63 x10-34 J.s.) x (3.00 x1017 nm/s)] /(1.55 x10-19 J)λ = 1280nm</span>
∆H = m x s x ∆T, where m is the mass of the reactants, s is the specific heat of the product, and ∆T is the change in temperature from the reaction.
