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Arturiano [62]
3 years ago
8

Which of these convert electric energy into kinetic energy?

Physics
2 answers:
Anna007 [38]3 years ago
8 0

Answer:

The answer is <em>Electric Motors</em> .

Explanation:

As <u>E</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>i</u><u>c</u><u> </u><u>m</u><u>o</u><u>t</u><u>o</u><u>r</u><u>s</u> take in electrical energy in order to operate it. So it change from electrical energy to kinetic emergy.

Natasha_Volkova [10]3 years ago
7 0

Answer:A vibration powered generator is a type of electric generator that converts the kinetic energy from vibration into electrical energy.

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A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the
valina [46]

Answer:

- 0.25m/s²

Explanation:

Given parameters:

Initial velocity  = 40m/s

Final velocity  = 30m/s

Time taken  = 40s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time.

 So;

  Acceleration  = \frac{Final velocity - Initial velocity }{time }  

 Acceleration  = \frac{30  - 40}{40}    =  - 0.25m/s²

This implies that the car will decelerate at a rate of 0.25m/s²

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3 years ago
Please help its homework
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It starts as a igneous rock and becomes metamorphic then sedimentary
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3 years ago
Light waves that cross from an air medium to a water medium will
il63 [147K]

C. change length and direction

Explanation:

The density of the material in which the light wave is travelling affects the speed of the wave. Different materials have different densities and they effect differently light waves which travel through them. Light waves may change direction at the boundary between two transparent materials, depending on material density. Density also impacts the speed of light. The denser the material, the slower light travels through it. The wavelength also decreases as light travels through the denser medium.

3 0
3 years ago
Question 10 (1 point)
torisob [31]

Answer:

It does not hit the students face because the speed of the balloon slows down as energy is lost through thermal.

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3 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is
Andreas93 [3]

Answer:

v=1.08\times 10^7\ m/s

Explanation:

Initial speed of the electron, u = 0

The charge per unit area of each plate, \dfrac{Q}{A}=1.69\times 10^{-7}\ C/m^2

Separation between the plates, d=1.75\times 10^{-2}\ m

An electron is released from rest, u = 0

Using equation of kinematics,

v^2-u^2=2ad..........(1)

Acceleration of the electron in electric field, a=\dfrac{qE}{m}............(2)

Electric field, E=\dfrac{\sigma}{\epsilon_o}............(3)

From equation (1), (2) and (3) :

v=\sqrt{\dfrac{2q\sigma d}{m\epsilon_o}}

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 1.69\times 10^{-7}\times 1.75\times 10^{-2}}{9.1\times 10^{-31}\times 8.85\times 10^{-12}}}

v = 10840393.1799 m/s

or

v=1.08\times 10^7\ m/s

So, the electron is moving with a speed of 1.08\times 10^7\ m/s before it reaches the positive plate. Hence, this is the required solution.

3 0
3 years ago
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