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Arturiano [62]
3 years ago
8

Which of these convert electric energy into kinetic energy?

Physics
2 answers:
Anna007 [38]3 years ago
8 0

Answer:

The answer is <em>Electric Motors</em> .

Explanation:

As <u>E</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>i</u><u>c</u><u> </u><u>m</u><u>o</u><u>t</u><u>o</u><u>r</u><u>s</u> take in electrical energy in order to operate it. So it change from electrical energy to kinetic emergy.

Natasha_Volkova [10]3 years ago
7 0

Answer:A vibration powered generator is a type of electric generator that converts the kinetic energy from vibration into electrical energy.

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As a planet's semimajor axis gets smaller, its speed will _______ and its period will _________ .
Rufina [12.5K]
Well first of all, a planet doesn't have a semimajor axis, although it's orbit does.

In an orbit with a smaller semimajor axis, the planet moves faster, and its orbital period is shorter.

That's why the International Space Station circles the Earth in less time than the Moon does.
4 0
3 years ago
Can an object with constant acceleration reverse its direction of travel? Can it reverse its direction twice? Explain.
Neko [114]

Answer:yes

Explanation:The constan acceleration means that it wont stop moving but if you kick it a different direction then it will change direction

6 0
3 years ago
In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube le
expeople1 [14]

Answer:

The  value  is   m \approx   310

Explanation:

From the question we are told that

     The  focal length of the objective is  f_o =  1.0 \ cm

    The  focal length of the eyepiece is  f_e  =  2.0 \  cm

    The  tube length is  L  =  25 \  cm

Generally the magnitude of the overall magnification is mathematically represented as

            m =  m_o  *  m_e

Where  m_o is the objective magnification which is mathematically represented as

        m_o  =  \frac{L}{f_o }

=>      m_o  =  \frac{25}{1 }

=>      m_o  =  25

m_e is the eyepiece magnification which is mathematically evaluated as

     m_e  =  \frac{L }{f_e }

     m_e  =  \frac{25 }{ 2}

      m_e  =  12.5 \  cm

So

    m =  25 * 12.5

     m \approx   310

6 0
3 years ago
The Atoms Family
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What question are you asking?
4 0
3 years ago
Amount of work done by a rotating object
Oduvanchick [21]
The work done by a rotating object can be calculated by the formula Work = Torque * angle.

This is analog to the work done by the linear motion where torque is analog to force and angle is analog to distance. This is Work = Force * distance.

An example will help you. Say that you want to calculate the work made by an engine that rotates a propeller with a torque of 1000 Newton*meter over 50 revolution.

The formula is Work = torque * angle.

Torque = 1000 N*m

Angle = [50 revolutions] *  [2π radians/revolution] = 100π radians

=> Work = [1000 N*m] * [100π radians] = 100000π Joules ≈ 314159 Joules of work.

 
5 0
3 years ago
Read 2 more answers
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