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nevsk [136]
3 years ago
8

A person supporting Eugene Talmadge for governor would have been MOST likely to belong to which occupation?

Physics
2 answers:
lisov135 [29]3 years ago
7 0

Answer:

B) Farmer

Explanation:

tee hee i just got this question :)))

tatyana61 [14]3 years ago
5 0

Answer:

B) Farmer

Explanation:

USA Test Prep tested. Is correct

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What's the process?
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Explanation:

Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.

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3 years ago
What is scientific inquiry? Who can use it and what does it involve?
torisob [31]
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3 years ago
Read 2 more answers
Tarzan swings back and forth on a
WARRIOR [948]

Answer:

Considering Tarzan as a point mass at point L and using the equation for a simple pendulum:

P = 2 pi (L / g)1/2

P^2 = 4 pi^2 L / g

L = g P^2 / (4 pi^2) = 9.8 m/s^2 * 7.27^2 s^2 / (4 pi^2) = 13.1 m

4 0
3 years ago
A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

\mu = IA

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

\tau = IAB

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

P = 2\pi r

r = \frac{P}{2\pi}

r = \frac{1.9}{2\pi}

r = 0.3025m,

The total Area of the loop would be given as,

A = \pi r^2

A = \pi 0.3025^2

A = 0.287m^2

Substituting at the equation of magnetic moment we have

\mu = (16*10^{-3})(0.287)

\mu = 4.58*10^{-3} A.m^2

Therefore the magnetic moment of the loop is 4.58*10^{-3}Am^2

PART B)  Replacing our values at the equation of torque we have that

\tau = IAB

\tau = (16*10^{-3})(0.287)(0.790)

\tau = 3.62*10^{-3}Nm

Therefore the torque exerted by the magnetic field is 3.62*10^{-3}Nm

6 0
3 years ago
An object is moving at a velocity of 3m/s. It accelerates to a velocity of 5.5m/s over a time of 9 s. What acceleration did it e
alexira [117]

Answer:

Acceleration(a) = \displaystyle\frac{v - u}{t}

v = final velocity = 5.5 m/s

u = initial velocity = 3 m/s

t = time = 9s

\displaystyle a = \frac{3-5.5}{9}

a = \displaystyle\frac{-2.5}{9}

a = -0.278 \ m/s^2 (approx)

3 0
3 years ago
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