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IceJOKER [234]
3 years ago
12

What is the mean of -71,-62,-88-38-89,15,-76

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0
71
62
88
38
89
76
-15 (i'm inversing everything to make it simple)
The mean is -69.28

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A building casts a shadow 48ft long. At the same time, a 40ft tall flagpole casts a shadow 9.6ft long
Karo-lina-s [1.5K]

Answer:

Sorry I just need points

7 0
3 years ago
Simplest form of 4500:80000 and 8100:144000​
a_sh-v [17]

9514 1404 393

Answer:

  • 9/160
  • 9/160

Step-by-step explanation:

Divide each number in the ratio by their greatest common divisor.

  4500 : 80000 = (4500/500) : (80000/500) = 9 : 160

  8100 : 144000 = (8100/900) : (144000/900) = 9 : 160

3 0
3 years ago
I need help ASAP!!
Studentka2010 [4]

Answer:

  D.  (x-5)^2 = 36

Step-by-step explanation:

If you add 11 to the given equation, you get ...

  x^2 -10x = 11

Then you can add the square of half the x-coefficient to complete the square.

  x^2 -10x +25 = 11 +25

  (x -5)^2 = 36 . . . . simplify to the appropriate form

5 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
The question is below could you explain in detail thank you so much!!!
Ivan
I think is 1863 m because if you use the formula for area 
8 0
3 years ago
Read 2 more answers
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