Answer: 63.88 atm
Explanation:
To answer this, we use the formula PV = nRT since the asumption is that the gas has an ideal behavior
where number of mole = 2.60 mol, R(gas constant) = 0.08205746 L atm/K mol,
T = 251 ∘C = (251 + 273) K = 524 K, Volume = 1.75 L
Making Pressure the subject of the formula, we have
P = nRT/V = 2.6 * 0.08205746 * 524/2.75 = 63.88 atm
Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is
KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
Rubbing leaves a balloon electrically
charged; the charged balloon polarizes the
wall.
Answer:
Molecules make scents. Aromatic ones (That is, containing rings of carbon atoms with delocalised electrons). Some unpleasant smells are due to hydrogen and sulphur groups.
Explanation:
The equilibrium expression shows the ratio
between products and reactants. This expression is equal to the concentration
of the products raised to its coefficient divided by the concentration of the
reactants raised to its coefficient. The correct equilibrium expression for the
given reaction is:<span>
<span>H2CO3(aq) + H2O(l)
= H3O+(aq) + HCO3-1(aq)
Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>
