With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
<h3>What is the surface area of a truncated prism?</h3>
The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:
A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)
A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²
A = 276 cm²
With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
To learn more on surface areas: brainly.com/question/2835293
#SPJ1
-6x-7+8=19 and then add your like terms so it’s -6x+1=19 and then subtract one on both sides so it’s -6x=18 so x=-3
4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ
hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)
I think it's 50%, tell me if my answer was right please
Answer:
72 55/76
Step-by-step explanation:
it's right trust me <3
