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SpyIntel [72]
3 years ago
12

What type of circuit is illustrated

Physics
1 answer:
Varvara68 [4.7K]3 years ago
4 0
The bulbs are in parallel.

The picture doesn't show enough of the circuit to tell
whether it's also open or shorted.  It may be either, or
it may be neither.
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6 0
2 years ago
The power of the kettle was 2.6 kW
faltersainse [42]

Answer:

Cp = 4756 [J/kg*°C]

Explanation:

In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.

Q = m*Cp*(T_f - T_i)/t

where:

Q = heat transfer = 2.6 [kW] = 2600[W]

m = mass of the water = 0.8 [kg]

Cp = specific heat of water [J/kg*°C]

T_f  = final temperature of the water = 100 [°C]

T_i = initial temperature of the water = 18 [°C]

t = time = 120 [s]

Now clearing the Cp, we have:

Cp = Q*t/(m*(T_f - T_i))

Now replacing

Cp = (2600*120)/(0.8*(100-18))

Cp = 4756 [J/kg*°C]

7 0
3 years ago
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ICE Princess25 [194]

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660V

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V=IR

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3 years ago
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Answer:2 and 4th one

Explanation:

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