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Morgarella [4.7K]
3 years ago
8

A 2.29N force is applied to the plunger of a hypodermicneedle.

Physics
1 answer:
Ede4ka [16]3 years ago
6 0

Answer:

0.04651 N

Explanation:

F_1 = Force on plunger = 2.29 N

d_1 = Diameter of plunger = 1.27 cm

d_2 = Diameter of needle = 0.181 cm

F_2  = Force on needle

From Pascal's law we have

\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1\times A_2}{A_1}\\\Rightarrow F_2=\dfrac{2.29\times \pi\dfrac{0.181^2}{4}}{\dfrac{\pi 1.27^2}{4}}\\\Rightarrow F_2=0.04651\ N

The force with which the fluid leaves the needle is 0.04651 N

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