3 years ago

A ball is thrown directly upwards. Is there a point of trajectory where the ball has zero acceleration

Physics

1 answer:

kotegsom [21]3 years ago

5 0

Answer:

Amplitude

Explanation:

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at the sewing store, ava bought a bag of buttons. 21 in all. 21 of the buttons were large. what percentage of the buttons wre la

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If she only has 21 buttons and all 21 of them are large, then all of her buttons are large. so 100% of the buttons would be large.

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3 years ago

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A ball is spun around in circular motion such that it completes 50 rotations in 25 s.

Leokris [45]

Answer:

(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.

Explanation:

Given that,

a ball is spun around in circular motion such that it completes 50 rotations in 25 s.

(1). Let T be the period of its rotation. It can be calculated as follows :

$T=\dfrac{25}{50}\\\\T=0.5\ s$

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

$f=\dfrac{50}{25}\\\\f=2\ Hz$

Hence, this is the required solution.

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3 years ago

Water flows over the edge of a waterfall at a rate of 1.2 x 10^6 kg/s. There are 50.0 m between the top and bottom of the waterf

Anit [1.1K]

Answer:

5.88×10⁸ W

Explanation:

Power = change in energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

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3 years ago

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A 40 kg boy on a skateboard throws a 2 kg ball at 20 m/s to the left. How fast did the boy move to the right on his skateboard?

sergey [27]

According to my examination I have confirmed that I do NOT repeat do NOT know this .

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3 years ago

Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23

Sloan [31]

Answer:

The ratio is $\frac{T_1}{T_2} = 3.965$

Explanation:

From the question we are told that

The radius of Phobos orbit is R_2 = 9380 km

The radius of Deimos orbit is $R_1 = 23500 \ km$

Generally from Kepler's third law

$T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }$

Here M is the mass of Mars which is constant

G is the gravitational constant

So we see that $\frac{ 4 * \pi^2 }{G * M } = constant$

$T^2 = R^3 * constant$

=> $[\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3$

Here $T_1$ is the period of Deimos

and $T_1$ is the period of Phobos

$[\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}$

=> $\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]$

=> $\frac{T_1}{T_2} = 3.965$

8 0

3 years ago