Question

If an aluminum skillet with 10.0 inch diameter weighs 3.00 pounds, What volume of aluminum does it contain? (The density of aluminum is 2.70g/cm3, 1.00 pound = 453.6g)

Answer 1

Answer:

The answer to your question is 504 cm³

Explanation:

Data

diameter = 10 in

mass = 3 pounds

density = 2.7 g/cm³

1 pound ----- 453.6 g

Process

1.- Convert pounds into grams using proportions

                             1 pound ---------------  453.6 g

                             3 pounds ------------   x

                             x = (3 x 453.6) / 1

                             x = 1360.8 g

2.- Calculate the volume of the skillet

Formula

density = $\frac{mass}{volume}$

Solve per volume

$volume = \frac{mass}{density}$

Substitution

$volume = \frac{1360.8}{2.70}$

Simplification and result

      volume = 504 cm³