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Free_Kalibri [48]
3 years ago
10

In a Lewis diagram for methane, which atom or atoms is outside

Chemistry
1 answer:
Alik [6]3 years ago
7 0
The hydrogen atoms are on the outside.
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Which statements describe the law of conservation of charge? Check all that apply.
AlekseyPX
The statements in accordance with the law of conservation of charge are:
A. The total charge of the reactants and products must be equal
B. The net charge of an isolated system remains constant

Both of these statements follow the law of conservation of charge which states that charge may neither be created nor destroyed, due to which the total charge in an isolated system (one in which charge can not move in or out of) remains constant.
5 0
2 years ago
Which amino acid is least likely to produce a hydrogen bond with water or polar molecules?
KonstantinChe [14]
9 amino acids (alanine, cysteine, glycine, isoleucine, leucine, methionine, phenylalanine, proline, valine) have no hydrogen donor or acceptor atoms in their side chains.
3 0
3 years ago
In today's experiment, Solutions A and B are prepared as follows.
hram777 [196]

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

<h3>D. 0.160</h3>
3 0
2 years ago
Select the correct answer.
muminat

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of Ag_2S = 2(107.87)+32.06  = 247.8 g per mol

The dimensional set up for the complete problem is:

0.0150L(\frac{2.50molAgNO_3}{1L})(\frac{1molAg_2S}{2molAgNO_3})(\frac{247.8gAg_2S}{1molAg_2S})

= 4.65gAg_2S

So, the correct choice is B. 4.65 g.


7 0
3 years ago
How do you find the number of neutrons in an element
e-lub [12.9K]

Answer:

Mass number -Atomic number

6 0
3 years ago
Read 2 more answers
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