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3 years ago

Solve this equation: x+21=20

2 answers:

6 0

<h3>Hey there! </h3><h3>x+21=20</h3><h3>x=20-21</h3><h3>x=-1</h3><h3>Hope this helps you!</h3><h3>#HaveAnAmazingDay</h3><h3> $GraceRosalia$ </h3>

____ [38]3 years ago

5 0

Answer:

x=20-21

x= -1

hope helps... :)

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For a binomial probability distribution, it is unusual for the number of successes to be less than μ − 2.5σ or greater than μ +

kirill [66]

Answer:The correct option is a)

The upper limit of successes that would be deemed to be usual is 5, so more than 5 successes would be unusual.

Step-by-step explanation:

The mean of a binomial distribution

μ= np where n=10 and p= 0.2 q= 1-p, q= 1-0.2=0.8

μ= 10×0.2=2

σ=√npq

σ=√10×0.2×0.8=1.26

Is unusual for the number of success to be greater than μ + 2.5σ.

= 2+2.5(1.26)

=5 approximately.

So it is unusual for it to be greater than 0.5. The right option Is a)

7 0

3 years ago

israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa

agasfer [191]

Lets solve our radical equation $\sqrt{x+6}-4=x$ step by step.

Step 1 add 4 to both sides of the equation:

$\sqrt{x+6} -4+4=x +4$

$\sqrt{x} +6=x+4$

Step 2 square both sides of the equation:

$\sqrt{x+6} =x+4$

$\sqrt{x+6}^2 =(x+4)^2$

$x+6=(x+4)^2$

Step 3 expand the binomial in the right hand side:

$x+6=x^2+8x+16$

Step 4 simplify the expression:

$0=x^2+8x-x+16-6$

$x^2+7x+10=0$

Step 5 factor the expression:

$(x+2)(x+5)=0$

Step 6 solve for each factor:

$x+2=0$ or $x+5=0$

$x=-2$ or $x=-5$

Now we are going to check both solutions in the original equation to prove if they are valid:

For $x=-2$

$\sqrt{x+6}-4=x$

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$

The solution $x=2$ is a valid solution of the rational equation $\sqrt{x+6}-4=x$ .

For $x=-5$

$\sqrt{x+6}-4=x$

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3\neq -5$

Since -3 is not equal to -5, the solution $x=-5$ is not a valid solution of the rational equation $\sqrt{x+6}-4=x$ ; therefore, $x=-5$ is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0

4 years ago

What is -4 3/8 - -1 1/4

Likurg_2 [28]

Answer:

Step-by-step explanation:

- 3 1/8

6 0

3 years ago

A soccer ball is kicked from ground level. The function y = -12x (x - 6) shows the height in feet) of the

enot [183]

Answer:

6 seconds

Step-by-step explanation:

Given

y = - 12x(x - 6)

When the ball hits the ground then height of ball is zero

let y = 0 , that is

- 12x(x - 6) = 0

Equate each factor to zero and solve for x

- 12x = 0 ⇒ x = 0 ← when ball is first kicked

x - 6 = 0 ⇒ x = 6 ← when the ball hits the ground.

The ball hits the ground after 6 seconds

8 0

3 years ago

PLEASE HELP MEEEEEEEEEEEEEEEEE

brilliants [131]

Answer:

A. .25

B. .95

C. .75

D. .42

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve this equation: x+21=20​

Solve this equation: x+21=20