The division equation that has a quotient of 13 is 1/1/13 = 13
<h3>How to determine the equation?</h3>
The given parameters are:
- Quotient = 13
- Dividend = Whole number
- Divisor = Unit fraction i.e. 1/n where n is an integer.
A division equation is represented as:
Dividend/Divisor = Quotient
Substitute 13 for the Quotient
Dividend/Divisor = 13
Recall that:
Unit fraction = 1/n
So, we have:
Dividend/1/n = 13
Let n = 13.
So, we have:
Dividend/1/13 = 13
This gives
13 * Dividend = 13
Divide both sides by 13
Dividend = 1
So, we have:
1/1/13 = 13
Hence, the division equation is 1/1/13 = 13
Read more about division equations at:
brainly.com/question/1622425
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Answer:
Step-by-step explanation: 3XY 3+5-X-2XY3=XY3+11 USE THE COMMUTATIVE PROPERTY TO REODER THE TERMS...3Y3+5-X-2XY3=XY3+11 COLLECT LIKE TERMS Y3+5-X-Y3X+11..Cancel equal terms on both sides of the equation 5-x=11 move constant to the right side and change its sign -x=11-5 subtract the numbers -x=6 final answer is X=-6
From what i see, i guess the answer may be B. it looks like it, but i dont really know.
The equation for that is V = 1/2 A x C x H
