All categories

3 years ago

Remember that it takes 2 electrons to form a bond how many bonds does CIO 3 - have, the chlorate ion

Chemistry

2 answers:

pogonyaev3 years ago

8 0

Answer:

3 bonds.

Explanation:

2 double bonds and one single bond.

ladessa [460]3 years ago

5 0

Answer:

3 bonds

Explanation:

solve this by doing the lewis structure for CIO3

You might be interested in

What is the temperature of 0.750 mol of a gas stored in a 6,050 mL cylinder al 221 atm?

Rasek [7]

Answer:

T = 246 K

Explanation:

Given that,

Number of moles, n = 0.750 mol

The volume of the cylinder, V = 6850 mL = 6.85 L

Pressure of the gas, P = 2.21 atm

We need to find the temperature of the gas stored in the cylinder. We know that,

PV= nRT

Where

R is gas constant

T is temperature

So,

$T=\dfrac{PV}{nR}\\\\T=\dfrac{2.21\times 6.85}{0.75\times 0.0821}\\T=245.85\ K$

T = 246 K

So, the temperature of the gas is equal to 246 K.

4 0

3 years ago

Which of the following can be changed in a chemical reaction?

DanielleElmas [232]

Answer:

Type of molecules

Explanation:

got it right

4 0

3 years ago

How many oxygen atoms are in 8.20 g Na 2SO 4?

dusya [7]

Answer:

No. of atom =

no.of moles x avagardro's number xatomicity

= weight /molar mass x No x atomicity

=8.2/142 x6.02x10^23 x 4

=0.346 x 10^23(approximately)

3 0

4 years ago

Consider the second-order reaction:

kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
$

Rate Law: $k[HI]^2
$

Rate constant of the reaction = k = $6.4\times 10^{-9} L/mol s$

Order of the reaction = 2

Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

$[A]=0.00345 mol/L$

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

5 0

4 years ago

Which type of electromagnetic wave has the most energy?

Leto [7]

Answer:

Gamma rays

Explanation:

6 0

3 years ago

Read 2 more answers