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Ludmilka [50]
3 years ago
10

What happens at a convergent boundary?

Physics
2 answers:
LenaWriter [7]3 years ago
8 0
Convergent boundaries form earthquakes, which forms mountains and islands.
SIZIF [17.4K]3 years ago
6 0

Answer:

Convergent plate boundaries are usually characterized by the convergent motion of the tectonic plates and the formation of a subduction zone, deep sea-oceanic trenches.

When the plates move towards each other, there forms a subduction zone where the denser plate goes below the lighter one. This subduction zone is basically identified by the presence of a narrow V-shaped type of depression, which is commonly known as the trench.

As the denser plate subducts into the layer of the asthenosphere, the rocks undergo partial melting and mixes with the magma. This magma is then brought upward into the over-riding plate, giving rise to the formation of volcanoes.

This type of plate boundary is responsible for the occurrence of deep-focus earthquakes.

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A man has a power of 90 W and mass 60 kg runs up a staircase in 40 s. If each staircase is 20cm high find the number of steps? (
Svetlanka [38]
I depends on three area of the staircase
4 0
3 years ago
A pencil rolls horizontally of a 1 meter high desk and lands .25 meters from the base of the desk. How fast was the pencil rolli
vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2} (2)

Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

\theta=0\° since we are told the pencil rolls <u>horizontally</u> before falling

t is the time since the pencil falls until it hits the ground

y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity, always acting vertically downwards

Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

Finally:

V_{o}=0.55 m/s

4 0
3 years ago
A tight knot can be easily opens by using a longer spanner. Give reasons
kobusy [5.1K]

It is because the effort distance is greater than the load distance

Explanation:

As we know, Effort×effort distance = load × load distance

So when effort distance is increases,

The effort decreases

So when the spanner’s handle is long

A tight knot can easily be opened by less effrot

I hope it helped

6 0
2 years ago
G (where g=9.8 m/s2). If an object’s mass is m=10. kg, what is its weight?
Semenov [28]
F_{w} =m*g \\ F_{w} =10*9.8=98N
7 0
3 years ago
How much energy in Joules (J) would an electric heater that draws 9.5 A when connected to a 120 V supply use if the heater were
leonid [27]
<h2>Energy used by heater is 8.21 x 10⁶ J</h2>

Explanation:

Energy = Power x Time

Power = Voltage x Current

Voltage = 120 V

Current = 9.5 A

Power = Voltage x Current

Power = 120 x 9.5 = 1140 W

Time = 2 hours = 2 x 60 x 60 = 7200 s

Energy = Power x Time

Energy = 1140 x 7200

Energy = 8208000 J

Energy used by heater is 8.21 x 10⁶ J

7 0
3 years ago
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