Question

A baseball has a mass of 0.145 kg. A professional pitcher throws a baseball 67 mi/h, which is 30.0 m/s. What is the magnitude of the momentum of the pitched baseball?

Answer 1

The concept of momentum tells us that it is equivalent to the product between the mass and the velocity of the object, that is to say that in general it can be written as

$p = mv$

Where,

m = mass

v = Velocity

Our values are given as,

$m = 0.145kg$

$v = 67mi/h = 30m/s$

Replacing we have that,

$p = (0.145)(30)$

$p = 12.45 kg\cdot m/s$

Therefore the magniude of the momentum of the pitched baseball is $12.45 kg\cdot m/s$

Answer 2

Answer:

Momentum = 0.145kg × 30m/s = 4.35kgm/s

The momentum of the pitched baseball is 4.35kgm/s

Explanation:

Momentum is the quantity of motion of a moving body, it is the product of mass and velocity of a moving body.

Momentum = mass × velocity = mv

In the case above,

Mass m = 0.145kg

Velocity v = 30m/s

Substituting the values; Momentum will be equal to,

Momentum = 0.145kg × 30m/s = 4.35kgm/s

The momentum of the pitched baseball is 4.35kgm/s