Responder:
A) ω = 565.56 rad / seg
B) f = 90Hz
C) 0.011111s
Explicación:
Dado que:
Velocidad = 5400 rpm (revolución por minuto)
La velocidad angular (ω) = 2πf
Donde f = frecuencia
ω = 5400 rev / minuto
1 minuto = 60 segundos
2πrad = I revolución
Por lo tanto,
ω = 5400 * (rev / min) * (1 min / 60s) * (2πrad / 1 rev)
ω = (5400 * 2πrad) / 60 s
ω = 10800πrad / 60 s
ω = 180πrad / seg
ω = 565.56 rad / seg
SI)
Dado que :
ω = 2πf
donde f = frecuencia, ω = velocidad angular en rad / s
f = ω / 2π
f = 565.56 / 2π
f = 90.011669
f = 90 Hz
C) Periodo (T)
Recordar T = 1 / f
Por lo tanto,
T = 1/90
T = 0.0111111s
Answer:
Both balls hit the ground simultaneously
Explanation:
Let´s call b₁ ( the ball dropped ) the equation for a free fall movement is, tacking as the origin of coordinates the level from which it was dropped
V = g*t ( since V₀ initial velocity is 0 )
In the case of projectile movement the equation for Vx and Vy (these speeds are independent)
are:
Vx = V₀x (constant) and Vy = Voy + g*t
Vy = V₀ * sin 0⁰ + g*t Vy = 0 + g*t
As we can see V is the same in both cases then the balls hit the ground simultaneously
20.9m = 1s
286.33m = 13.7s
To answer this you would multiply both sides by the amount of seconds she ran. The answer however is that she ran as far as 286.33m.
What surprises me about ancient beliefs systems is how they different point of views
V= frequency x wavelength
The average velocity of a microwave is 3x10^8m/s.
3x10^8m/s= (.05m) x frequency
f= 6x10^9Hz