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Virty [35]
3 years ago
12

How do scientists conduct investigations

Physics
1 answer:
DENIUS [597]3 years ago
4 0
Steps of a scientific investigation include identifying a research question or problem, forming a hypothesis, gathering evidence, analyzing evidence, deciding whether the evidence supports the hypothesis, drawing conclusions, and communicating the results.
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The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103
gavmur [86]

I think the question need to use extrapolation. FInd the linear function of the first and second data. And then, the anwser is 5.4 liters.

8 0
3 years ago
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True or False: It would be easier to run on a planet with high gravity than one with less gravity.
LUCKY_DIMON [66]
True! It would be easier
3 0
3 years ago
A 15.0-kilogram mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the
Mars2501 [29]
The answer is 570 J. The kinetic energy has the formula of 1/2mV². The total work in this process W= 1/2m(V2²-V1²) = 1/2 * 15.0 * (11.5²-7.50²) = 570 J.
7 0
4 years ago
An electron is released from rest at a distance of 0.570 m from a large insulating sheet of charge that has uniform surface char
Lelu [443]

Explanation:

Formula to calculate the electric field of the sheet is as follows.

          E = \frac{\sigma}{2 \epsilon_{o}}

And, expression for magnitude of force exerted on the electron is as follows.

            F = Eq

So, work done by the force on electron is as follows.

           W = Fs

where,     s = distance of electron from its initial position

                  = (0.570 - 0.06) m

                  = 0.51 m

First, we will calculate the electric field as follows.

              E = \frac{\sigma}{2 \epsilon_{o}}

                 = \frac{4.60 \times 10^{-12}C/m^{2}}{2 \times 8.854 \times 10^{-12}C^{2}/N m^{2}}

                 = 0.259 N/C

Now, force will be calculated as follows.

                 F = Eq

                    = 0.259 N/C \times 1.6 \times 10^{-19} C

                    = 0.415 \times 10^{-19} N

Now, work done will be as follows.

                    W = Fs

                        = 0.415 \times 10^{-19} N \times 0.51 m

                        = 2.12 \times 10^{-20} J

Thus, we can conclude that work done on the electron by the electric field of the sheet is 2.12 \times 10^{-20} J.

3 0
4 years ago
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An atom of 6/2 He decays by beta decay. What atom is left after decay
olya-2409 [2.1K]

Answer:

6/3 LI

Explanation:

7 0
3 years ago
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