Answer: Molar concentration of the tree sap have to be 0.783 M
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 19.6 atm
i = Van't hoff factor = 1 (for non-electrolytes)
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:


Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C
It will occupy 18 L volume when the pressure is changed to 0. 5 atm and the temperature remain constant.
Calculation,
According to Boyle law, the pressure of a given quantity of gas varies inversely with its volume at constant temperature.
.....(i)
is initial pressure = 3 atm
is initial volume = 3L- k is constant
(ii)
is final pressure = ?
is final volume = 0.5atm- k is constant
Combining equation (i) and (ii). we get,

3 atm× 3L=
× 0.5atm
= 3 atm× 3L/0.5atm = 18 L
Boyle law used during respiration or breathing.
To Learn more about Boyle law
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<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.
b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.
</span>and % will be 60%.
Answer:
132.94 kilo joules
Explanation:
We are given;
- Mass of benzene solution is 850 g
- Temperature change from 95°C to 3° C = 92° C or 92 K
We are required to determine the energy released by the cooling of benzene.
Taking the specific heat capacity of liquid benzene as 1.7 kJ/kg/K
Then we can determine the amount of heat energy released by using the formula;
Heat = Mass × specific heat × change in temperature
= 0.85 kg × 1.7 kJ/kg/K × 92 K
= 132.94 kilo joules
Therefore, the heat released by cooling benzene is 132.94 kilo joules