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3 years ago

Can you find a salmander in the desert or rainforest?

Chemistry

1 answer:

vodka [1.7K]3 years ago

6 0

You can find it in rainforest because they like damp places.

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Solve

stiv31 [10]

The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

T1 = initial temperature
T2 = final temperature
V1 = initial volume
V2 = final volume

V1 = 9L
V2 = ?
T1 = 325K
T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

7 0

3 years ago

Interpret the electron configuration

Svetach [21]

Answer:

Ca for calcium

20 electrons

2-2s electron

6 0

3 years ago

Is the color of the flam a test for the nitrate polyatomic ion in each of the compounds?

Valentin [98]

brainly.com/question/8471573#respond

4 0

3 years ago

Help please and thank you for who ever

Korolek [52]

Answer:the first one

Explanation:

7 0

3 years ago

Read 2 more answers

1. convert 8.43 x 1025 atoms of Fe to moles

Luba_88 [7]

Answer:

The number of moles of Fe are, 139.9 moles.

The number of moles of CO are, 7.89 moles.

The number of moles of Al are, $4.04\times 10^{-4}$ moles.

Explanation :

As we know that 1 mole of substance contains $6.022\times 10^{23}$ atoms or molecules.

Part 1:

As, $6.022\times 10^{23}$ atoms of Fe present in 1 mole

So, $8.43\times 10^{25}$ atoms of Fe present in $\frac{8.43\times 10^{25}}{6.022\times 10^{23}}\times 1=139.9$ mole

Thus, the number of moles of Fe are, 139.9 moles.

Part 2:

As, $6.022\times 10^{23}$ molecules of CO present in 1 mole

So, $4.75\times 10^{24}$ molecules of CO present in $\frac{4.75\times 10^{24}}{6.022\times 10^{23}}\times 1=7.89$ mole

Thus, the number of moles of CO are, 7.89 moles.

Part 3:

As, $6.022\times 10^{23}$ atoms of Al present in 1 mole

So, $2.43\times 10^{20}$ atoms of Al present in $\frac{2.43\times 10^{20}}{6.022\times 10^{23}}\times 1=4.04\times 10^{-4}$ mole

Thus, the number of moles of Al are, $4.04\times 10^{-4}$ moles.

4 0

4 years ago