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3 years ago

If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?

1 answer:

3 0

<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.

b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.

</span>and % will be 60%.

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You want to place a piece of glass tubing into a ruber stopper after the tubing has been fire polished and cooled. This is best

igor_vitrenko [27]

Answer:

All of the above

Explanation:

This is correct

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2 years ago

Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi

xenn [34]

Conjugate base of Propanoic acid ( $CH_{3}CH_{2}COOH$ is propanoate where -COOH group gets converted to -CO $O^{1-}$ . The structure of conjugate base of Propanoic acid is shown in the diagram.

The $p^{H}$ above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

$p^{H}$ = $p^{k_{a}$ + log $\frac{[Conjugate base]}{[acid]}$ =4.9+log $\frac{90}{10}$ =5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0

3 years ago

An electric range burner weighing 699.0 grams is turned off after reaching a temperature of 482.0°C, and is allowed to cool down

jasenka [17]

Answer:

0.42 J/gºC

Explanation:

We'll begin by calculating the heat energy used to heat up the water. This can be obtained as follow:

Mass (M) of water = 560 g

Initial temperature (T₁) = 22.7 °C

Final temperature (T₂) = 80.3 °C.

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) absorbed =?

Q = MC(T₂ – T₁)

Q = 560 × 4.18 (80.3 – 22.7)

Q = 2340.8 × 57.6

Q = 134830.08 J

Finally, we shall determine the specific heat capacity of the burner. This can be obtained as follow:

Mass (M) of burner = 699 g

Initial temperature (T₁) = 482.0°C

Final temperature (T₂) = 22.7 °C

Heat (Q) evolved = – 134830.08 J

Specific heat capacity (C) of the burner =?

Q = MC(T₂ – T₁)

–134830.08 = 699 × C (22.7 – 482.0)

–134830.08 = 699 × C × –459.3

–134830.08 = –321050.7 × C

Divide both side by –321050.7

C = –134830.08 / –321050.7

C = 0.42 J/gºC

Therefore, the specific heat capacity of the burner is 0.42 J/gºC

8 0

2 years ago

On July 4, 2020, America turned 7.69 x 10^9

iogann1982 [59]

America's age = 243.85 years

<h3>Further explanation</h3>

When converting units, list and multiply all the units until you find the unit you want

Time unit conversion

1 year = 365 days

1 day = 24 hours

1 hour = 3600 s

7.69 x 10⁹ seconds to years :

$\tt =7.69\times 10^9~s\times \dfrac{1`hour}{3600~s}\times \dfrac{1~day}{24~hours}\times \dfrac{1~years}{365~days}\\\\=\dfrac{7.69\times 10^9}{3600\times 24\times 365}\\\\=\boxed{\bold{243.85~years}}$

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3 years ago

The molecule <br> mass of sodium oxide na2o is

maxonik [38]

it is 61.97894 g/mol

7 0

2 years ago

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