The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>
Given that
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies
When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles
<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
Anhydrous Copper sulfate is 39.81 percent copper and 60.19 percent sulfate by mass, and in its blue, hydrous form, it is 25.47% copper, 38.47% sulfate (12.82% sulfur) and 36.06% water by mass.
Answer:
High melting point,High density,Nonreactive
Explanation:
The following are the Properties of transition elements:
They have large charge/radius ratio. They are harder and they have high densities;.They have high melting and boiling points.They form compounds which are paramagnetic. They show variable oxidation states. They form colored ions and compounds. Compounds are formed with profound catalytic activity. Stable complexes are formed by them.
When Comparing with the alkali metals present in group 1 and the alkaline Earth metals that are present in group 2, the transition metals are considered to be much less reactive. They do not react fast with water or oxygen, which contributes to their resistance to corrosion.
