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lora16 [44]
3 years ago
6

Okay help please will give brainlist

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

b.

Explanation:

hope that helped you

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1 mole of a gas occupies 22.4 L at ________
artcher [175]

Answer: At STP, one mole (6.02 × 1023 representative particles) of any gas occupies a volume of 22.4 L (Figure below). A mole of any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm).

Explanation:

That the answer

8 0
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What is the volume of 4.78g of O2 gas at STP?
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Answer:

Explanation:

The trick here is to realize that if you know the volume of a gas at STP, you can use the fact that

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Under STP conditions:

1 mole of an ideal gas = 22.7 L

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

In your case, you know that your sample of gas occupies

2.28 L

under STP conditions, which are currently defined as a pressure of

100 kPa

and a temperature of

0

∘

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This means that your sample will contain

2.28

L

⋅

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

1 mole gas

22.7

L

=

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1

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3.78 g

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0.10044

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1

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⋅

3.78 g

0.10044

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=

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Since this is the mass of

1

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molar mass = 37.6 g mol

−

1

−−−−−−−−−−−−−−−−−−−−−−−

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