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ANEK [815]
3 years ago
15

Complete the following: (2x +5y)(2x − 5y)= ____ - _____

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

(2x +5y)(2x − 5y)  = {4x^{2}  - 25y^{2}

Step-by-step explanation:

(2x +5y)(2x − 5y) is the given equation.

Now, the <u>ALGEBRAIC IDENTITY</u> states that:

(a+ b)(a-b) = a^{2}  - b^{2}

Here, comparing a = 2x  and b = 5y,

we get (2x +5y)(2x − 5y)  = (2x)^{2}  - (5y)^{2}

on further solving the right side, we get

(2x +5y)(2x − 5y)  = {4x^{2}  - 25y^{2}

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alan has 12-half pound chocolate bars. it take 1.5 of chocolate, broken into chunks to make a batch of cookies. how many batches
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12 \div 1.5 = 8

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2 years ago
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Omar, Hala and Lujain got paid a total of $240 for cleaning neighborhood cars. They split the money in the ratio of 5: 9: 10. Ho
Levart [38]

Answer:

Total amount Omar earn = $120

Step-by-step explanation:

Given:

Total amount Omar, Hala and Lujain got paid = $240

Ratio of money Omar, Hala and Lujain got paid = 5:9:10

Find:

Total amount Omar earn

Computation:

Total amount Omar earn = [Total amount Omar, Hala and Lujain got paid][Omar'ratio / Total ratio]

Total amount Omar earn = [240][5 / (5+9+10)]

Total amount Omar earn = [240][5 / (24)]

Total amount Omar earn = [24][5]

Total amount Omar earn = $120

5 0
2 years ago
Three-quarters the product of two numbers x and y
serg [7]

Answer:

xy=3/4

Step-by-step explanation:

since it says the "product"

it is x(y)

3/4 goes after the = sign

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2 years ago
amy and her family were traveling during their vacation. she looked at her watch at point 1 in the diagram below, and then again
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An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
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