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storchak [24]
4 years ago
12

A student argues that y=x9 does not represent a proportional relationship between x and y because we need to multiply one variab

le by the same constant to get the other one and not divide it by a constant. Do you agree or disagree with this student
Mathematics
1 answer:
kobusy [5.1K]4 years ago
5 0

A proportional relationship can we written as follows:-

y = mx

Where 'y' is dependent variable, 'x' is independent variable, and 'm' is the slope or we can say 'm' is constant of proportionality.

'm' can take any value whether negative or positive, decimal or whole number. 'm' is a real number.

The given problem is y = x/9 and student says we can only multiply constant, and not divide. We disagree with this comment because m= 1/9 is correct.

So y = 1/9 x makes sense.

y = x/9 represents a proportional relationship.

You might be interested in
A+b=95<br> 4a+1.50b=267.5
Papessa [141]

9514 1404 393

Answer:

  • a=50
  • b=45

Step-by-step explanation:

We can subtract the second equation from 4 times the first:

  4(a +b) -(4a +1.5b) = 4(95) -(267.5)

  2.5b = 112.5 . . . . . simplify

  b = 45 . . . . . . . . . . divide by 2.5

  a = 95 -b = 50 . . . find 'a'

The solution is (a, b) = (50, 45).

5 0
3 years ago
Equations
Vera_Pavlovna [14]

Step-by-step explanation:

I hope this is correct.

5 0
3 years ago
Angle 2 is 110 degrees. Allen claims that we do not have enough information to solve for angle 1. Is he correct? Why or why not?
devlian [24]

Allen's claim that we do not have enough information to solve for angle 1 is incorrect

<h3>How to calculate the measure of angle 1</h3>

Given that:

Angle 2 = 110 degrees

Angle 1 and angle 2, are the only angles on the straight line.

So, we have:

\angle 1 + \angle 2 = 180

Substitute 110 for angle 2

\angle 1 + 110 = 180

Subtract 110 from both sides

\angle 1 = 70

The measure of angle 1 is 70 degrees.

So, we can conclude that Allen's claim is incorrect

Read more about angle theorems at:

brainly.com/question/6766389

3 0
3 years ago
Solve each linear-quadratic system algebraically. Show all work.
a_sh-v [17]

Answer:

(5, - 8 ) and (- 1, 4 )

Step-by-step explanation:

Given the 2 equations

y = - x² + 2x + 7 → (1)

y = - 2x + 2 → (2)

Substitute y = - 2x + 2 into (1)

- 2x + 2 = - x² + 2x + 7 ← subtract - x² + 2x + 7 from both sides

x² - 4x - 5 = 0 ← in standard form

(x - 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 5 → y = - 2(5) + 2 = - 10 + 2 = - 8 ⇒ (5, - 8)

x = - 1 → y = - 2(- 1) + 2 = 2 + 2 = 4 ⇒ (- 1, 4)

5 0
3 years ago
Simplify the expression below.<br> 7(2x+2)-9(-1+6x)
MaRussiya [10]
Use the distributive property to simplify.

7(2x+2)-9(-1+6x) \\ 7(2x)+7(2)-9(-1)-9(6x) \\ 14x+14+9-54x

Group like terms and add/subtract.

14x-54x+14+9\\\boxed{-40x+23}
7 0
3 years ago
Read 2 more answers
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