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pickupchik [31]
3 years ago
7

Solve the following quadratic equation 6x2 – 7x = 20

Mathematics
2 answers:
siniylev [52]3 years ago
5 0

Answer:

<h2>x = 5/2 , x = - 4/3</h2>

Step-by-step explanation:

6x² - 7x - 20 = 0

Using method of factorization

Rewrite - 7x as a difference

That's

6x² + 8x - 15x - 20 = 0

Factor the expression

That's

2x( 3x + 4) - 5( 3x + 4) = 0

Which is

(2x - 5) (3x + 4) = 0

2x - 5 = 0

2x = 5

Divide both sides by 2

x = 5/2

3x + 4 = 0

3x = - 4

Divide both sides by 3

x = -4/3

Hope this helps you

Marat540 [252]3 years ago
4 0

Answer:

x = -4/3 or x = 5/2

Step-by-step explanation:

given  6x² - 7x = 20

There are several ways to solve this, we'll choose to use the quadratic formula:

Recall that for a quadratic equation ax² + bx + c = 0

x = [ -b±√(b²-4ac)  ] / 2a

in our case, if we rearrange the equation, we will get:

6x² - 7x -20 = 0

comparing this with the general form of the quadratic equation above, we can see that

a = 6, b = -7 and c = -20

substituting these into the equation:

x = [ -b±√(b²-4ac)  ] / 2a

x = { -(-7)±√[(-7)²-4(6)(-20)] } / 2(6)

x = -4/3 or x = 5/2

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MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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3 years ago
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Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

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M(\frac{x1+x2}{2},\frac{y1+y2}{2})

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student 1

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substitute in the formula

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substitute in the formula

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substitute in the formula

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so

<u>The midpoint is equal to (-1,4)</u>

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substitute in the formula

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substitute in the formula

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so

<u>The midpoint is equal to (-1,4)</u>

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