Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
A = 7
b = -18
c = -52
Do you know what the Quadratic formula is to solve?
Answer:
y - 7 = 2(x - 1)
Step-by-step explanation:
Going from (-3, -1) to (1, 7), x increases by 4 and y by 8. These numbers are the 'run' and 'rise' of the line, respectively. Thus, the slope of the red line is m = rise/run = m = 8/4 = 2.
Using the point-slope formula and the point (1, 7), we get:
y - 7 = 2(x - 1)
Volume of sphere = 4/3 x pi x r^3
Volume of large sphere:
4/3 x 3.14 x 14^3 = 11488.21 cubic cm
Volume of smaller sphere:
4/3 x 3.14 x 2^3 = 33.49 cubic cm
Number of small spheres = volume of large sphere/ volume of small sphere
11488.21 / 33.49 = 343.03
Round to 343 small spheres
