Answer:
x
^2/
6
--------------------------------------------------------------------------
Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
Answer:
The first five terms are;
-3,-7,11,-29,69
Step-by-step explanation:
The recursive definition of the sequence is
,
and
.
When n=3, we obtain;
.
.
.
.
When n=4
.
.
When n=5
.
.
Therefore the first five terms are;
-3,-7,11,-29,69
B
5/4 times 4/5X=8/1 times 5/4
X=40/4
X=10
Y = 7sin(30) = 3.5
_________