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OLEGan [10]
3 years ago
13

A person pulls a box across a floor. Which is the correct analysis of the situation? A. The box moves forward because the person

pulls forward slightly harder on the box than the box pulls backward on the person. B. Because action always equals reaction, the person cannot pull the box. The box pulls backward just as hard as the person pulls forward, so there is no motion. C. The person gets the box to move by giving it a tug during which the force on the box is momentarily greater than the force exerted by the box on the person. D. The person's force on the box is as strong as the force of the force of the box on the person, but the frictional force on the person is forward and large while the backward frictional force on the box is small. E. The person can pull the box forward only if it weights more that the box.
Physics
1 answer:
vekshin13 years ago
6 0

Answer:

D. The person's force on the box is as strong as the force of the box on the person, but the frictional force on the person is forward and large while the backward frictional force on the box is small.

Explanation:

When a bag is pulled, then it involves a person’s force on the box meaning there is an opposite force which is equal to the force of the box on the person.

When the box is pulled, there is a forward frictional force on the person which is big when compared to the backward frictional force which is small. This positive difference is responsible for the movement of the box.

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A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float
storchak [24]

Answer:

 t ’= \frac{1450}{0.6499 + 2 v_r},  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= \frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \  + 2 \ v_r}

      t ’= \frac{1450}{0.6499 + 2 v_r}

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= \frac{ 1450}{ 0.6499 + 2 \ 1}

      t ’= 547.19 s

8 0
3 years ago
What type of reaction is occurring when you activate an instant cold pack?
kobusy [5.1K]

Answer:

Endothermic, because energy is absorbed (A)

Explanation:

The reaction that take place in the instant cold pack causes the surroundings around it, including the bag that contains it. When the bag loses heat to the cold pack, the cold pack absorbs the heat, thereby causing the environment (the bag) to be cold.

3 0
3 years ago
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Andreyy89

Answer:

electrons

Explanation:

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6 0
3 years ago
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Which statement best explains why an object weight less on mercury than it does on earth
larisa [96]
This is because planet weigh different amount and force of gravity is different from planet to planet for example if your weigh on earth is 100 pound than on mercury is only 78 pounds
5 0
4 years ago
A coil of wire is comprised of 5 turns, has a current of 2 mA running through it, and a net magnetic field at its center of B is
VARVARA [1.3K]

Answer:

<em>20cm</em>

Explanation:

<em>A coil wire comprises of 5 turns,  it has a current of 2mA </em>

<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>

<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>

<em>Therefore 40/2mA = 20</em>

6 0
3 years ago
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