A coil of wire is comprised of 5 turns, has a current of 2 mA running through it, and a net magnetic field at its center of B is
equal to start fraction mu naught over 40 end fraction times T. What is the radius of the coil of wire?
1 answer:
Answer:
<em>20cm</em>
Explanation:
<em>A coil wire comprises of 5 turns, it has a current of 2mA </em>
<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>
<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>
<em>Therefore 40/2mA = 20</em>
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