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3 years ago

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A coil of wire is comprised of 5 turns, has a current of 2 mA running through it, and a net magnetic field at its center of B is

equal to start fraction mu naught over 40 end fraction times T. What is the radius of the coil of wire?

1 answer:

VARVARA [1.3K]3 years ago

6 0

Answer:

<em>20cm</em>

Explanation:

<em>A coil wire comprises of 5 turns, it has a current of 2mA </em>

<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>

<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>

<em>Therefore 40/2mA = 20</em>

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Put the value in the equation

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<u>Given data :</u>

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Hence we can conclude that the answers to your question are as listed above.

Learn more about electric potential : brainly.com/question/25923373

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