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Murrr4er [49]
3 years ago
7

In the electromagnetic spectrum, _______ is the _______ frequency color of visible light. A. green; highest B. red; lowest C. vi

olet; lowest D. blue; highest
Physics
2 answers:
MissTica3 years ago
8 0
D.) In the electromagnetic spectrum, "Blue" is the "Highest" <span>frequency color of visible light.

Hope this helps!</span>
MaRussiya [10]3 years ago
5 0
Red is the lowest because it has the shortest wavelengths
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a runner covers the last straigjt stretch of a race in 4 s. during that time, he speeds up from 5m/s to 9m/s.
PtichkaEL [24]

During that final period of time,
his acceleration is
                                (9 m/s - 5 m/s) / (4 sec) = 1 m/s² .

Did you have a question to ask ?

8 0
3 years ago
I need help can someone help me pls
pychu [463]

Answer:

copper

Explanation:

4 0
3 years ago
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What is the kinetic energy of an automobile with a mass of 1252 kg traveling at a speed of 12 m/s?
torisob [31]
KE = 1/ 2 * 1252 * 144
 as  KE = 1/2 * m * v ^2
 = 90144 J



4 0
3 years ago
A snail travels 300 cm in 4 minutes.calculate speed of snail in m/s
LekaFEV [45]

Answer:

\frac{0.0125m}{s}

Explanation:

In order to solve this question we need to know that  speed = \frac{distance}{time}. Then we need to convert 4 minutes into seconds and cm into m. We can do that by multiplying the number of minutes by 60 (because there is 60 seconds in one minute) and dividing the number of cm by 100 (because there is 100 cm in one m). So.......

4min = 4 x 60s = 240s

300cm = 300/100 m = 3m

Now we know that distance = 300m, and that the time = 4min = 240s ⇒

⇒ speed=\frac{distance}{time} = \frac{3m}{240s} = \frac{0.0125m}{s}

5 0
3 years ago
The volume flow rate of the water supplied by a well is 2.0×10−4m3/s.The well is 40.0 m deep. (a) What is the power output of th
MaRussiya [10]

Answer:

a). P=78.4W

b). P=392kPa

c.) It must be at the bottom

Explanation:

Given:

Volume flow V_f=2.0x10^{-4}m^3/s

Well depp h=40.m

a.

The power output of the pum

W=F*d

F=m*g

m=p*V=1000kg/m^3*2.0x10^{-4}m^3}=0.2Kg

W=m*g*d=0.2kg*9.8m/s^2*40.0m=78.4kg*m^2/s^2

W=78.4J

P=\frac{W}{t}=\frac{78.4J}{1s}=78.4W

b.

The pressure of difference the pum

ΔP=p*g*y'

ΔP=1000kg/m^3*9.8m/s^2*40.0m=392x10^3Pa

P=392kPa

c.

It must be at the bottom since the pressure difference is greater than atmospheric pressure, so it wouldn't be able to lift the water all the way  

4 0
4 years ago
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