Answer:
The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Explanation:
Suppose we find the coefficient of friction and the acceleration of the 100 kg block during the time that the 60 kg block remains in contact.
Given that,
Mass of block = 60 kg
Acceleration = 2.0 m/s²
Mass = 100 kg
Horizontal force = 340 N
Let the frictional force be f.
We need to calculate the frictional force
Using balance equation

Put the value into the formula



We need to calculate the coefficient of friction
Using formula of friction force




We need to calculate the acceleration of the 100 kg block
Using formula of newton's law




Hence, The coefficient of friction and acceleration are 0.37 and 2.2 m/s²
Answer:
666 bc its on its way to my house
Explanation:
An equation relating the length that you measure l to the ship's proper length l0 is
l =l0/y. This is further explained below.
<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>
Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.
In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.
Read more about Lorentz transformation
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Answer:
16 m/s
Explanation:
Given that
y momentum = 0.080 *25 = 2
x momentum = 0.075*20 = 1.5
total momentum = √(4 + 2.25)
Total momentum = √6.25
Total momentum = 2.5
total mass = mass of x and y momentum = 0.075 + 0.080 = 0.155
speed of mass center = total momentum / total mass = 2.5/0.155 = 16.
And thus, the speed of the center of mass of this two-particle system at this instant is 16 m/s
You can't tell without knowing the values of the resistors. Whichever resistor has less resistance (less ohms) will have more current flowing through it.