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OverLord2011 [107]
3 years ago
7

An electron is acted on by two electric forces, one of 2.7×10-14 N acting upward and a second of 5.8×10-14 N acting to the right

. What is the magnitude of the electric field at the electron’s location?
Physics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

3.99×10⁵ N/C

Explanation:

Assuming both force forms a right angle triangle,

Using Pythagoras theorem,

a² = b²+c²................... Equation 1

Where a= resultant of the two forces, b = the force acting upward, c = the force acting to the right.

make a the subject of the equation.

a = √(b²+c²)....................... Equation 2

Given: b = 2.7×10⁻¹⁴ N, c = 5.8×10⁻¹⁴ N.

Substitute into equation 2

a = √[(2.7×10⁻¹⁴)²+( 5.8×10⁻¹⁴ )²]

a = √[7.28×10⁻²⁸)+(33.64×10⁻²⁸)]

a = √(40.92×10⁻²⁸)

a = 6.397×10⁻¹⁴ N.

But,

F = Eq ................ Equation 3

Where E = Electric Field, q = charge of an electron, F = electric force.

make E the subject of the equation,

E = F/q ............. Equation 4

Given: F = 6.397×10⁻¹⁴ N, q = 1.602×10⁻¹⁹  C.

Substitute into equation 4

E =  6.397×10⁻¹⁴/(1.602×10⁻¹⁹ )

E = 3.99×10⁵ N/C

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Assuming the bar has no weight where does the fulcrum (the top point of the tringle) need to be positioned for the two sides to
Inessa05 [86]

Fulcrum need to be positioned balanced with weight on both the sides following law of lever.

What is the physical law of the lever?

  • It is the foundation for issues with weight and balance. According to this rule, a lever is balanced when the weight multiplied by the arm on one side of the fulcrum, which serves as the pivot point for the device, equals the weight multiplied by the arm on the opposing side.
  • The lever is balanced, in other words, when the sum of the moments about the fulcrum is zero.
  • The situation in which the positive moments (those attempting to turn the lever clockwise) equal the negative moments is known as this (those that try to rotate it counterclockwise).
  • Moving the weights closer to or away from the fulcrum, as well as raising or lowering the weights, can alter the balance point, or CG, of the lever.

Learn more about the Fulcrum with the help of the given link:

brainly.com/question/16422662

#SPJ4

3 0
1 year ago
Which would be the best metal to use for the insulated wire?
katrin2010 [14]
Copper, because it has the lowest specific electrical resistance.

specific electrical resistance aka volume resistivity is a fundamental property of a material that quantifies how strongly that material opposes the flow of electric current. A low resistivity indicates a material that readily allows the flow of electric current.
6 0
3 years ago
A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
Svetlanka [38]

Answer:

a = 1.152s

b = 0.817 m

c = 7.29m/s

Explanation: let the following

From the first equation of linear motion

V = u+at..........1

parameters be represented as :

t = Time taken

v = Final velocity

a = Acceleration due to gravity = 9.8m/s²

u = Initial velocity = 4 m/s

s = Displacement

V = 0

Substitute the values into equation 1

0 = 4-9.8(t)

-4 = -9.8t

t = 4/9.8

t = 0.408s

From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

S= 1.632-4.9(0.166)

S = 1.632-0.815

S = 0.817m

Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

0.554 =t^2

t =√0.554

t = 0.744s

Hence, her feet were in the air for 0.744+0.408seconds

= 1.152s

Also recall from equation 1

V= u+at

V = 0+9.8(0.744)

V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

Finally,

a = 1.152s

b = 0.817 m

c = 7.29m/s

4 0
2 years ago
.A box falls to the ground from a delivery truck traveling at 30 m/s. After hitting the road, it slides 45 m to
Romashka-Z-Leto [24]

Answer:

t = 3 seconds

Explanation:

Given that,

Initial speed, u = 30 m/s

Final speed, v = 0

It slides 45 m to rest.it take the box to come to rest

We need to find how long it take the box to come to rest.

Let a be the acceleration and t is time.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(30)^2-u^2}{2(45)}\\\\=10\ m/s^2

Now finding time.

t=\dfrac{v-u}{a}\\\\t=\dfrac{30-0}{10}\\\\t=3\ s

So, the required time is 3 seconds.

8 0
3 years ago
As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the ave
DedPeter [7]

Answer:

-29.2\times 10^{3} N

Explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time=\Delta t=1.3 s

We have to find the average force exerted on the car.

Average force=\frac{change\;in\;momentum}{\Delta t}

F_{avg}=\frac{mv-mu}{1.3}

F_{avg}=\frac{1900(0)-1900(20)}{1.3}

F_{avg}=\frac{-38000}{1.3}=-29.2\times 10^{3} N

Hence, the average force exerted on the car that hits a line of water barrels=-29.2\times 10^{3} N

8 0
3 years ago
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