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kondaur [170]
3 years ago
5

On a windless day, two identical balls P and Q are dropped from the top and the middle of a tower at exactly the same time as sh

own .Which will be more: the time taken by P to reach the middle of the tower ,or the time taken by Q to reach the ground?
Physics
1 answer:
Kruka [31]3 years ago
3 0

Answer: time is the same

Explanation: the distance(H) is the same in each case .

we drop the balls , no drag force using basic kimnematics

y =gt*t/2  , yo=0 , vo=0 , y=H  , so : t= sqrt(2H/g)

comment: if distance H starts to grow....we could begin to note a difference  because of gravity g is smaller as we go up

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AP Physics I, shouldn't be too hard.
Nana76 [90]

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision =  9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

5 0
3 years ago
Apples are stored in a container (width = length = 3.5 ft) that is filled to a depth of 2.75 feet. If the unit density of an app
Agata [3.3K]

Answer:

The mass of the apples in the box are 1145.95 lb.

Explanation:

Given that,

Width = 3.5 ft

length = 3.5 ft

Depth = 2.75 feet

Density = 49.3 lb/ft³

We need to calculate the volume

Using formula of volume

V=l\times h\times b

Put the value

V=3.5\times3.5\times2.75

V=33.6875\ ft^3

We need to calculate the mass

Using formula of density

\rho=\dfraxc{m}{V}

m=\rho\timesV

Put the value into the formula

m=49.3\times33.6875

m=1660.79\ lb

But porosity is 31 % so apples is 69% mass of total container.

So, Total mass in pounds is

M=\dfrac{69}{100}\times1660.79

M=1145.95\ lb

Hence, The mass of the apples in the box are 1145.95 lb.

8 0
3 years ago
A circular coil of radius 5.0 cm and resistance 0.20 Ω is placed in a uniform magnetic field perpendicular to the plane of the c
DedPeter [7]

Answer:

The induced current in the coil at the time 2 s is 0.00263 A

Explanation:

The equation for induced emf is equal to:

\epsilon =-\frac{d}{dt} (BAcos\theta )

Where

B = magnetic field

A = area

θ = angle

\epsilon =-Acos0\frac{d}{dt} B\\\epsilon =-(\pi r^{2} )\frac{d}{dt} (0.5e^{-0.2t} )\\\epsilon =0.1 (\pi r^{2} )e^{-0.2t}

For t = 2 s

\epsilon =0.1*\pi *0.05^{2} *e^{-0.2*2} =5.26x10^{-4} V

The induced current is:

I=\frac{\epsilo }{R} =\frac{5.26x10^{-4} }{0.2} =0.00263A

3 0
3 years ago
Which of these characteristics would best help a student who is focused on reaching academic goals?
Anarel [89]
Answer: Responsibility
5 0
3 years ago
What do the sound waves made by the bell carry to your ear
ad-work [718]

Answer:

When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.

Explanation:

3 0
1 year ago
Read 2 more answers
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