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Effectus [21]
3 years ago
10

If you go back in time to kill your grandfather, you would pop out of existence, but if you pop out of existence your grandfathe

r wouldn't die. but then you would pop back into existence to kill him again. so would it be an endless loop? help me figure this out
Physics
2 answers:
crimeas [40]3 years ago
8 0
I bet that is actually true. But where in the world did you get this idea of?
katen-ka-za [31]3 years ago
8 0
No. That isn't specifically how time travel works.

When you time travel, you are taking your body from your current time and traveling through universal zones to go back to the specific time you wanted. You would just be absent from the present time as if you were at home, or something.
You would go back into time and you would have to be able to keep yourself hidden enough, because if anyone recognized you (such as family), it would alter time itself.
Along with, if you killed your grandfather then your parent (from such grandfather), may or may not exist, which could alter your own existence, changing time and space itself, altering the universe itself.

So no, it would not be an infinite loop. You would just be absent from your present time until you decided to return back to it.
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3 years ago
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Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
givi [52]

Answer:

A. speed = 7.14 Km/s

B. distance = 1820.7 Km

Explanation:

Given that: a = 14.0 m/s^{2}, t = 8.50 minutes.

But,

t = 8.50 = 8.50 x 60

  = 510 seconds

A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

u = 0

So that,

v = 14 x 510

 = 7140 m/s

The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.

B. the distance traveled can be determined by applying second equation of motion.

s = ut + \frac{1}{2}at^{2}

where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.

u = 0

s = \frac{1}{2}at^{2}

  = \frac{1}{2} x 14 x (510)^{2}

 = 7 x 260100

 = 1820700 m

The distance that the shuttle has traveled during the given time is  1820.7 Km.

5 0
2 years ago
A uniform rod is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The moment of inertia of t
emmasim [6.3K]

Answer:

Angular acceleration = 6.37rad/sec²

Approximately, Angular acceleration =

6.4 rad/sec²

Explanation:

Length of the rod = 2.0m long

Inclination of the rod (horizontal) = 30°

Mass of the rod is not given so we would refer to it as = M

Rotational Inertia of the Rod(I) = 1/3ML²

Angular Acceleration = ?

There is an equation that shows us the relationship between Torque and Angular acceleration.

The equation is :

Torque(T) = Inertia × Angular Acceleration

Angular acceleration = Torque ÷ Inertia

Where:

Torque = L/2(MgCosθ)

Where M = Mass

L = Length = 2.0m

θ = Inclination of the rod (horizontal) = 30°

g = Acceleration due to gravity = 9.81m/s²

Inertia = 1/3ML²

Angular Acceleration =  (Mass × g × Cos (30°) × (L÷2)) ÷ 1/3ML²

Angular Acceleration =

(3 × g × cos 30°) ÷ 2× L

Angular Acceleration = (3 × 9.81m/s² × cos 30°) ÷ 2× L

Angular Acceleration = 3 × 9.81m/s² × cos 30°) ÷ 2× 2.0m

Angular Acceleration = 6.37rad/sec²

Approximately Angular Acceleration =

6.4rad/sec²

5 0
3 years ago
Describe the difference between the velocity graph made walking at a steady rate and the velocity graph made at an increasing ra
levacccp [35]

Answer:

The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0

On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.

8 0
3 years ago
A bowling ball is dropped off the top of the Eiffel Tower. If the Eiffel Tower is 300 meters
patriot [66]

Answer:

7.82 s

Explanation:

Given:

Δy = 300 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(300 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 7.82 s

5 0
3 years ago
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