Answer:
Explanation:
applied Mechanics and its Growing Utilisation of Theoretical Mechanics.\
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Answer:
250 A
Explanation:
B = 5 x 10^-5 T, r = 1 m
Let current be i.
the magnetic field due to a straight current carrying conductor is given by
B = μ0 / 4π x 2i / r
5 x 10^-5 = 10^-7 x 2 x i / 1
i = 250 A
Answer:
(a) The resistance R of the inductor is 2480.62 Ω
(b) The inductance L of the inductor is 1.67 H
Explanation:
Given;
emf of the battery, V = 16.0 V
current at 0.940 ms = 4.86 mA
after a long time, the current becomes 6.45 mA = maximum current
Part (a) The resistance R of the inductor
Part (b) the inductance L of the inductor
where;
L is the inductance
R is the resistance of the inductor
t is time
Therefore, the inductance is 1.67 H
Well depending on what current the heater pulls im going to assume about 13, and 13A for the hair dryer, thats 26A on the 40A circuit.
I dont see how a lightbulb could overload the circuit.
Anyway, assuming the circuit is overloaded by some really big heater- the circuit would trip, the fuse would go and remain off. Most houses are fitted with seperate circuits for lights and sockets, so the light may remain on depending on the breaker board. - the reason for them all being able to run with the sudden overload may be due to a surge.
One solution to this is not to put such a large heater on the circuit with other appliances.
Another may be to dry your hair in the dark
Saturnnnnnnnnnnnnnn..........
