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Vinil7 [7]
3 years ago
6

URGENT: Two horizontal forces act on an object on a surface. There is a 20 Newton applied force to the left and a sliding fricti

onal force of 5 Newtons to the right.
What is the net force on the object?
Physics
1 answer:
anygoal [31]3 years ago
7 0

Answer:

xbzcfhkuvy

Explanation:

dvdvxvdzdx

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An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c
KiRa [710]

Acceleration can be defined as the change of speed in an instant of time, that is

a = \frac{v_f-v_i}{\Delta t}

Here,

v_f = Final velocity

v_i = Initial velocity

\Delta t = Change in time

From this expression we will calculate the requested values replacing the variables in each of the given terms

PART A) The values under this condition are:

v_f = 5.3m/s

v_i = 15m/s

\Delta t = 10.4s

Replacing,

a = \frac{5.3m/s-(15m/s)}{10.4s}

a = -0.93m/s^2

PART B ) The values under this condition are:

v_f = -15m/s

v_i = -5.3m/s

\Delta t = 10.4

Replacing,

a = \frac{-(15m/s)-(-5.3m/s)}{10.4s}

a = -0.93m/s^2

Therefore the acceleration in the second time interval is -0.93m/s^2

PART C) The values under this condition are:

v_f = -15m/s

v_i = 15m/s

\Delta t = 10.4

Replacing,

a = \frac{-15m/s-(15m/s)}{10.4s}

a = -2.9m/s^2

6 0
3 years ago
You apply a force of 500 N to 150 N/m. how much does it stretch? Show the equation you are using, plus the values into the equat
jolli1 [7]

Answer:

3.33m

Explanation:

Given parameters:

Force applied  =500N

Elastic constant  = 150N/m

Unknown:

Amount of stretch or extension  = ?

Solution:

To solve this problem use the expression below:

    F  = k e

F is the force applied

k is the elastic constant

e is the extension

  So;

           500  = 150 x e

             e  = \frac{500}{150}    = 3.33m

3 0
3 years ago
Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel across a 30 V potential difference t
Goshia [24]

Answer:

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5 0
3 years ago
In the diagram, what is happening to the temperature at Point B? Question 6 options: A. The temperature is rising as the molecul
raketka [301]
<span> B. The temperature is not rising because the heat is being used to break the connections between the molecules </span>
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3 years ago
Read 2 more answers
A bird flies overhead from where you stand at an altitude of 270.0ĵ m and at a velocity horizontal to the ground of 14.0î m/is.
Varvara68 [4.7K]

Answer:

L = 8694 Kg.m²/s

Explanation:

r = 270 ĵ m

v = 14 î m/s

m = 2.3 kg

θ = 90º

L = ?

We can apply the equation

L = m*v*r*Sin θ

L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s

8 0
3 years ago
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