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liraira [26]
3 years ago
5

an object is dropped from a height of 25 meters. at what velocity will it hit the ground? a 7.0 m/s b 11 m/s c 22 m/s d 49 m/s e

70 m/s
Physics
1 answer:
kipiarov [429]3 years ago
6 0
Assuming that the object starts at rest, we know the following values:

distance = 25m
acceleration = 9.81m/s^2 [down]
initial velocity = 0m/s

we want to find final velocity and we don't know the time it took, so we will use the kinematics equation without time in it:

Velocity final^2 = velocity initial^2 + 2 × acceleration × distance

Filling everythint in, we have:

Vf^2 = 0^2 + (2)(-9.81)(-25)
The reason why the values are negative is because they are going in the negative direction

Vf^2 = 490.5

Take the square root of that

Final velocity = 22.15m/s which is answer c
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In diving to a depth of 248 m, an elephant seal also moves 296 m due east of his starting point. What is the magnitude of the se
Vinvika [58]

Answer:

The displacement is 386.16m

Explanation:

A seal dives to a depth of 248m. To find displacement, we must calculate the resultant vectors which will give us the displacement

R= sqrt(vector1+vector2)

Since this is a right angle triangle

R= sqrt(248^2 + 296^2)

R= sqrt(149120)

R= 386.16m

Displacement = 386.16m

4 0
3 years ago
an object with a mass of 2.4 kg has a force of 12.6 N applied to it. What is the resulting acceleration of the object? WITH PROO
Scorpion4ik [409]
Newton’s Law: F = MA
A = F/M (change equation)
12.6 N/ 2.4 kg = 5.25
Answer: acceleration is 5.25 m/s^2
3 0
3 years ago
A projectile is launched with an initial velocity of (40 m/s), at an angle of (30°) above
zlopas [31]

Answer:

330.5  m

Explanation:

In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .

The maximum height will be calculated as;

h=\frac{v^2_isin^2\alpha }{2g}

where ∝ is the angle of launch = 30°

vi= initial launch velocity = 40 m/s

g= 10 m/s²

h= 40²*sin²40° / 2*10

h={1600*0.4132 }/ 20

h= 661.1/2 = 330.5  m

8 0
2 years ago
The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with
kotykmax [81]

Answer:

D_{B}=1173.98m\\D_{C}=675.29m

Explanation:

If we express all of the cordinates in their rectangular form we get:

A = (1404.77 , 655.06) m

B = A + ( -D_{B} *sin(41) , -D_{B} * cos(41) )

C = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )

Since we need C to be (0,0) we stablish that:

C = (0,0) = A + B + ( -D_{C} *cos(20) , D_{C} * sin(20) )

That way we make an equation system from both X and Y coordinates:

A_{x} + B_{x} + C_{x} = 0

A_{y} + B_{y} + C_{y} = 0

Replacing values:

1404.77 - D_{B}*sin(41) - D_{C}*cos(20) = 0

655.06 - D_{B}*cos(41) + D_{C}*sin(20) = 0

With this system we can solve for both Db and Dc and get the answers to the question:

D_{B}=1173.98m

D_{C}=675.29m

7 0
3 years ago
A projectile is launched with speed of 128 m/s, at an angle of 60° with the horizontal. After 2.0 s, what is the vertical compon
Natali5045456 [20]

Answer:

a) 91 m/s

b) 111 m/s

Explanation:

v = u + at

v = 128sin60 + (-9.8)(2.0) = 91.25125... m/s

v = √(vx² + vy²) = √((128cos60)² + 91.25125²) = 111.4575... m/s

5 0
3 years ago
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