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tankabanditka [31]
3 years ago
5

(b) A piece of wood of volume 0.6 m² floats in water. Find the volume

Physics
1 answer:
enot [183]3 years ago
6 0

Answer:

Explanation:

Let the volume below water be v . Then

buoyant force = v d g where d is density of water , g is acceleration due to gravity

= v x 1000 x g

weight of wood piece = volume x density of wood x g

= .6 x 600 x g

for equilibrium while floating

buoyant force = weight

= v x 1000 x g  =  .6 x 600 x g

v = .36 m²

volume above water or volume exposed = .6 - .36

= .24 m²

When immersed completely ,

buoyant force = .6 x 1000 x 9.8

= 5880 N

weight of wood

=  .6 x 600 x g

= 3528 N

buoyant force is more than the weight . In order to equalise them for floating with full volume in water

weight required = 5880 - 3528

= 2352 N.

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Explanation:

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The distance center of gravity from left = x

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At the balance point: m_1x_1=m_2x_2

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x=1.1338 m

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3 years ago
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¿Cuál de las siguientes magnitudes es derivada?
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Explanation:

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Volume is a derived quantity because it requires one to use different measurements to determine it. For instance, in the case of a cube, the length, width and height of the cube are all needed to calculate volume.

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What happens when a negatively charged object A is brought near a neutral object B?
castortr0y [4]

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2 years ago
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A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the neg
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Answer:

2.1x10^6m/s

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